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Point Slope Form of a Line

How is point slope form used to write the equation of a line through a given point with a given slope?

Subject: Math Algebra Chapter: Equations Topic: Linear Equation Solver Answer included
point slope form equation of a line linear equation slope formula slope-intercept form standard form two-point method rise over run
Accepted answer Answer included

Point slope form

Point slope form gives an equation of a line when one point on the line and the slope are known. The standard statement is \(y - y_1 = m(x - x_1)\), where the fixed point is \((x_1, y_1)\) and the slope is \(m\).

Core relationship. A line with slope m passing through (x1, y1) satisfies

\[\boxed{\,y - y_1 = m(x - x_1)\,}\]

Every \((x,y)\) on the line makes the “change in \(y\)” equal to \(m\) times the “change in \(x\)”.

Meaning from the slope definition

The slope between two distinct points \((x_1,y_1)\) and \((x,y)\) on the same non-vertical line is \[ m = \frac{y - y_1}{x - x_1}\quad (x \ne x_1). \] Multiplying by \((x - x_1)\) yields \(y - y_1 = m(x - x_1)\), which is exactly point slope form.

Equivalent line forms and conversions

Point slope form is one of several equivalent ways to write the same linear equation. Expanding or rearranging changes the appearance but not the geometric line.

Form Equation What is immediately visible
Point slope form \(y - y_1 = m(x - x_1)\) A specific point \((x_1,y_1)\) and slope \(m\)
Slope-intercept form \(y = mx + b\) Slope \(m\) and \(y\)-intercept \(b\)
Standard form \(Ax + By = C\) Integers \(A,B,C\) often preferred for systems and elimination

Expanding point slope form gives slope-intercept form: \[ y - y_1 = m(x - x_1) \;\Longrightarrow\; y = mx + (y_1 - mx_1). \] The intercept is \(b = y_1 - mx_1\). Rearranging further provides standard form \(Ax + By = C\) by clearing denominators and collecting terms.

Two points and point slope form

When two points \((x_1,y_1)\) and \((x_2,y_2)\) are known with \(x_2 \ne x_1\), the slope is \[ m = \frac{y_2 - y_1}{x_2 - x_1}. \] Substituting this \(m\) into point slope form produces a valid equation for the line through both points.

Special cases

Vertical lines have undefined slope and do not fit point slope form. A vertical line through \((x_1,y_1)\) is described by \[ x = x_1, \] which fixes the \(x\)-coordinate for every point on the line.

Worked example

A line passes through \((-2, 5)\) with slope \(m = \frac{3}{4}\). Point slope form is \[ y - 5 = \frac{3}{4}(x - (-2)) = \frac{3}{4}(x + 2). \] Expanding produces slope-intercept form: \[ y - 5 = \frac{3}{4}x + \frac{3}{2} \;\Longrightarrow\; y = \frac{3}{4}x + \frac{13}{2}. \] Clearing denominators gives a standard form: \[ 4y = 3x + 26 \;\Longrightarrow\; 3x - 4y = -26. \]

Point slope form illustrated with a slope triangle A coordinate plane showing a line through the point (-2, 5) with slope 3/4. A right triangle indicates run 4 and rise 3. -6 -4 -2 0 2 4 6 8 10 12 -2 0 2 4 6 8 10 (-2, 5) run 4 rise 3 m = 3/4 Legend line given point run rise slope y − 5 = (3/4)(x + 2) point slope form
The plotted line passes through (-2, 5). The green “run 4” and orange “rise 3” form a slope triangle, showing \(m = \frac{\text{rise}}{\text{run}} = \frac{3}{4}\) in point slope form.

Common pitfalls

Sign errors in \(x - x_1\) and \(y - y_1\) are the most frequent source of incorrect equations; using \(x - (-2)\) as \(x + 2\) and \(y - 5\) exactly as written keeps the point anchored.

Fractional slopes require consistent distribution: \(m(x - x_1)\) means the slope multiplies the entire parenthesis.

Vertical lines correspond to \(x = x_1\) rather than point slope form because the slope is undefined.

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