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Match each algebraic expression to an equivalent form

Identify the equivalent expression for each of the expressions below.

Subject: Math Algebra Chapter: Algebraic Expressions and Polynomials Topic: Factoring and Simplifying Algebraic Expressions Answer included
identify the equivalent expression for each of the expressions below equivalent expressions simplify expressions distributive property combine like terms factoring difference of squares rational expression simplification
Accepted answer Answer included

Match each algebraic expression to an equivalent form

Equivalent expressions have the same value for every input where the original expression is defined. Simplification is valid when algebraic identities are used correctly and any domain restrictions remain unchanged after cancellations.

Expressions

(1) \(3(2x-5)+4x\)

(2) \(\dfrac{x^2-9}{x-3}\)

(3) \(2(x+1)^2-2(x^2+1)\)

(4) \(\dfrac{6x^2y}{3xy^2}\)

(5) \(\dfrac{\sqrt{50}}{\sqrt{2}}\)

Answer choices

A. \(10x-15\)

B. \(x+3\), with \(x\neq 3\)

C. \(4x\)

D. \(\dfrac{2x}{y}\), with \(x\neq 0\) and \(y\neq 0\)

E. \(5\)

Equivalence map: expressions flowing to simplified forms Five original expressions appear in colored boxes on the left. Arrows point to simplified equivalent forms on the right. A small note highlights that canceling a factor preserves a domain restriction, such as x not equal to 3. Equivalent expressions: the same value on the same domain Arrows show a correct simplification ending in a matching answer choice (A–E). Original expressions Equivalent forms (1) 3(2x − 5) + 4x Distributive property + like terms (2) (x² − 9) / (x − 3) Factor: x² − 9 = (x − 3)(x + 3) (3) 2(x + 1)² − 2(x² + 1) Expansion + cancellation (4) (6x²y) / (3xy²) Cancel common factors; keep restrictions (5) √50 / √2 Radical quotient → √(50/2) A 10x − 15 B x + 3 Restriction: x ≠ 3 C 4x D 2x / y Restrictions: x ≠ 0, y ≠ 0 E 5 Domain restrictions stay with the original expression Example: (x² − 9)/(x − 3) simplifies to x + 3, but x = 3 remains excluded because the original denominator becomes 0.
The diagram shows each expression converging to a simplified equivalent form. Cancellations in rational expressions remove a factor algebraically but do not remove the original restriction that the canceled factor cannot be zero.

Equivalence and domain

An equivalence statement \(E_1(x)=E_2(x)\) in algebra means equality for every \(x\) in the domain of \(E_1\). When a simplification involves a denominator, the excluded values that make the original denominator zero remain excluded after simplification.

Work and matches

(1) \(3(2x-5)+4x\)

\[ 3(2x-5)+4x = (6x-15)+4x = 10x-15 \]

Match: A

(2) \(\dfrac{x^2-9}{x-3}\)

\[ \frac{x^2-9}{x-3} = \frac{(x-3)(x+3)}{x-3} = x+3,\quad x\neq 3 \]

Match: B

(3) \(2(x+1)^2-2(x^2+1)\)

\[ 2(x+1)^2-2(x^2+1) = 2(x^2+2x+1) - (2x^2+2) = (2x^2+4x+2) - 2x^2 - 2 = 4x \]

Match: C

(4) \(\dfrac{6x^2y}{3xy^2}\)

\[ \frac{6x^2y}{3xy^2} = \frac{6}{3}\cdot\frac{x^2}{x}\cdot\frac{y}{y^2} = 2\cdot x \cdot \frac{1}{y} = \frac{2x}{y},\quad x\neq 0,\ y\neq 0 \]

Match: D

(5) \(\dfrac{\sqrt{50}}{\sqrt{2}}\)

\[ \frac{\sqrt{50}}{\sqrt{2}}=\sqrt{\frac{50}{2}}=\sqrt{25}=5 \]

Match: E

Final matching table

Expression Equivalent choice Equivalent form Domain notes
(1) \(3(2x-5)+4x\) A \(10x-15\) All real \(x\)
(2) \(\dfrac{x^2-9}{x-3}\) B \(x+3\) \(x\neq 3\)
(3) \(2(x+1)^2-2(x^2+1)\) C \(4x\) All real \(x\)
(4) \(\dfrac{6x^2y}{3xy^2}\) D \(\dfrac{2x}{y}\) \(x\neq 0,\ y\neq 0\)
(5) \(\dfrac{\sqrt{50}}{\sqrt{2}}\) E \(5\) Real values; \(\sqrt{2}\neq 0\)

Common pitfalls

Cancellation across a fraction changes the appearance of an expression but does not change which inputs are allowed; excluded values from the original denominator remain excluded. Another frequent error is distributing a coefficient incorrectly, such as treating \(3(2x-5)\) as \(6x-5\) instead of \(6x-15\).

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