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Graph of the Relation S: Domain, Range, and Function Test

The graph of the relation S is shown below. What are the domain and range of S, and does the relation represent a function?

Subject: Math Algebra Chapter: Functions Topic: Domain and Range Calculator Answer included
the graph of the relation s is shown below relation S graph domain from graph range from graph vertical line test relation vs function ordered pairs from graph piecewise relation
Accepted answer Answer included

the graph of the relation s is shown below

Relation \(S\) is represented in the coordinate plane by a curved piece, a vertical segment, and one isolated point. The domain consists of all \(x\)-values that appear on the graph, and the range consists of all \(y\)-values that appear on the graph.

Graph of the relation S with a curved piece, a vertical segment, and an isolated point A coordinate grid shows a purple parabola segment from x=-4 to x=0, a teal vertical segment at x=2 from y=-2 to y=2, and a red isolated point at (4,3). A legend identifies each component. x y S Components of relation S Curved piece for \(-4 \le x \le 0\) Vertical segment at \(x = 2\) Isolated point at \((4, 3)\) Reading rules Domain: x-values that occur on the graph Range: y-values that occur on the graph Function status: vertical line test
The domain is the set of all horizontal coordinates present on the graph; the range is the set of all vertical coordinates present on the graph.

Assumed mathematical description of S

A concrete interpretation consistent with the displayed graph is the union of three pieces:

\(S = \{(x,(x+2)^2-1)\,:\,-4 \le x \le 0\}\ \cup\ \{(2,y)\,:\,-2 \le y \le 2\}\ \cup\ \{(4,3)\}.\)

Domain of S

The domain is the set of all \(x\) for which at least one point \((x,y)\) lies in \(S\). The curved piece contributes all \(x\) from \(-4\) through \(0\), the vertical segment contributes \(x=2\), and the isolated point contributes \(x=4\). Therefore, \[ \mathrm{Dom}(S) = [-4,0]\ \cup\ \{2,4\}. \]

Range of S

The range is the set of all \(y\) for which at least one point \((x,y)\) lies in \(S\). On the curved piece \(y=(x+2)^2-1\) for \(-4 \le x \le 0\), the minimum occurs at the vertex \(x=-2\), giving \(y=-1\), and the maximum on that interval is \(y=3\) (at \(x=-4\) and \(x=0\)). The vertical segment at \(x=2\) covers all \(y\) from \(-2\) to \(2\), and the isolated point adds \(y=3\) (already included). Therefore, \[ \mathrm{Ran}(S) = [-2,3]. \]

Function status

A function assigns at most one \(y\)-value to each \(x\)-value. The vertical segment at \(x=2\) contains multiple points \((2,y)\) with different \(y\)-values (for example \((2,-1)\) and \((2,1)\)), so the vertical line \(x=2\) intersects the graph more than once. The relation does not represent a function.

Property Result Graph-based justification
Domain \(\,[-4,0]\cup\{2,4\}\,\) All \(x\)-values used by the curved piece, the vertical segment, and the isolated point
Range \(\,[-2,3]\,\) Vertical segment reaches down to \(-2\); curved piece and isolated point reach up to \(3\)
Function No At \(x=2\), multiple \(y\)-values occur (vertical line test fails)

Common pitfalls

  • Endpoint inclusion: filled endpoints indicate inclusion of boundary values in intervals such as \([-4,0]\) and \([-2,2]\).
  • Domain vs. range: horizontal coverage corresponds to the domain, vertical coverage corresponds to the range.
  • Function test confusion: a graph can contain curved pieces and still fail to be a function if any vertical line intersects it more than once.
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