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Point-Slope Form of a Line and How to Use It

How is the point slope form used to write the equation of a line given a point \((x_1,y_1)\) and slope \(m\), and how can it be converted to slope-intercept form?

Subject: Math Algebra Chapter: Equations Topic: Linear Equation Solver Answer included
point slope form linear equation slope point-slope equation slope-intercept form equation of a line algebra coordinate geometry
Accepted answer Answer included

The point slope form is a standard algebraic form for a linear equation that uses one known point on the line and the slope. It is especially efficient when the slope \(m\) and a point \((x_1,y_1)\) are given directly.

Point slope form (definition):

\[ y - y_1 = m(x - x_1). \]

Here, \(m\) is the slope and \((x_1,y_1)\) is any point on the line.

Why the point slope form works

Slope is defined as “rise over run” between two points \((x_1,y_1)\) and \((x,y)\) on the same line:

\[ m=\frac{y-y_1}{x-x_1}\quad (x\ne x_1). \]

Multiply both sides by \((x-x_1)\) to isolate the vertical change:

\[ y-y_1=m(x-x_1), \]

which is exactly the point slope form. This equation represents all points \((x,y)\) that maintain the same slope relative to \((x_1,y_1)\).

How to write an equation using point slope form

Given a slope \(m\) and a point \((x_1,y_1)\), substitute into \(\,y-y_1=m(x-x_1)\,\) and simplify if desired.

Worked example

Construct the line with slope \(m=2\) passing through \((x_1,y_1)=(1,3)\). This is a typical point slope form situation.

\[ y-3 = 2(x-1). \]

Converting point slope form to slope-intercept form

Slope-intercept form is \(y=mx+b\). To convert, expand and solve for \(y\).

\[ y-3 = 2(x-1) \]

\[ y-3 = 2x-2 \]

\[ y = 2x+1 \]

General conversion rule: Starting from \(y-y_1=m(x-x_1)\), expand to get

\[ y = mx + (y_1 - mx_1). \]

Therefore the intercept is \(\,b = y_1 - m x_1\).

Quick comparison of common linear forms

Form Equation Best used when
Point slope form \(y-y_1=m(x-x_1)\) A point and slope are given
Slope-intercept form \(y=mx+b\) Slope and y-intercept are needed quickly for graphing
Standard form \(Ax+By=C\) Integer coefficients are preferred or constraints are given in standard form

Visualization: line from point slope form

The graph below shows the example line \(y-3=2(x-1)\), which simplifies to \(y=2x+1\). The marked point \((1,3)\) lies on the line, and a second point \((2,5)\) illustrates the slope \(m=2\) (rise \(2\), run \(1\)).

Common mistakes to avoid

  • Mixing up the point: the form must be \(y-y_1=m(x-x_1)\). The subtraction signs are tied to the chosen point \((x_1,y_1)\).
  • Sign errors when \(x_1\) or \(y_1\) is negative: for example, if \(x_1=-4\), then \(x-x_1=x-(-4)=x+4\).
  • Confusing \(m\) with an x-intercept or y-intercept: in point slope form, \(m\) is strictly the slope.

Summary

The point slope form \(y-y_1=m(x-x_1)\) is derived directly from the slope definition and is ideal for writing a linear equation from a given point and slope. Expanding and isolating \(y\) converts it to slope-intercept form \(y=mx+b\) with \(b=y_1-mx_1\), which is often convenient for graphing and interpretation.

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