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Spontaneous Change

General Chemistry • Spontaneous Change Entropy and Gibbs Energy

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Entropy Change of the Universe — Second Law (ΔSuniv)

Spontaneity test at temperature \(T\): \(\Delta S_{\text{univ}}=\Delta S_{\text{sys}}+\Delta S_{\text{surr}}\). For a process exchanging heat \(q_{\text{sys}}\) with large surroundings at \(T\), \(\displaystyle \Delta S_{\text{surr}}=-\dfrac{q_{\text{sys}}}{T}\). Under constant-pressure conditions with negligible \(PV\) work other than expansion, \(q_{\text{sys}}=\Delta H\), so \(\displaystyle \Delta S_{\text{surr}}=-\dfrac{\Delta H}{T}\).

\[ \begin{aligned} \Delta S_{\text{univ}} &= \Delta S_{\text{sys}} + \Delta S_{\text{surr}} \\ &= \Delta S_{\text{sys}} - \dfrac{\Delta H}{T} \end{aligned} \]

J·mol⁻¹·K⁻¹
Inputs are on a molar basis. Output \(\Delta S_{\text{univ}}\) is in J·mol⁻¹·K⁻¹ (per reaction as written).
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Enter \(\Delta S_{\text{sys}}\), \(\Delta H\), and \(T\); then click “Calculate”.

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Frequently Asked Questions

What does Delta S_univ mean for spontaneity?

Delta S_univ is the total entropy change of the universe (system + surroundings). A process is spontaneous when Delta S_univ > 0, nonspontaneous when Delta S_univ < 0, and reversible at the ideal limit when Delta S_univ = 0.

What formula does the calculator use for spontaneous change?

It uses Delta S_univ = Delta S_sys + Delta S_surr with Delta S_surr = -Delta H/T for a large surroundings reservoir at temperature T. Under constant pressure with only pV work, q_sys = Delta H, which gives the -Delta H/T term.

Why does temperature need to be in kelvin for Delta H/T?

Entropy calculations require absolute temperature, so T must be in kelvin. If you enter °C, the calculator converts it to K before evaluating the -Delta H/T term.

When is Delta S_surr = -Delta H/T a good approximation?

It applies when the surroundings behave like a large thermal reservoir whose temperature does not change appreciably. It is commonly used for constant-pressure processes where the heat exchanged by the system equals Delta H.