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Entropy Boltzmann's View

General Chemistry • Spontaneous Change Entropy and Gibbs Energy

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Boltzmann Entropy — \(S = k_{\mathrm B}\ln W\)

Boltzmann’s relation links entropy \(S\) to the number of accessible microstates \(W\). We also use the two-state form \(\Delta S = k_{\mathrm B}\ln(W_2/W_1)\).

\[ S = k_{\mathrm B}\ln W \qquad\text{and}\qquad \Delta S = k_{\mathrm B}\ln\!\left(\frac{W_2}{W_1}\right) \]

dimensionless
J·K⁻¹ (system)
dimensionless
dimensionless
J·K⁻¹ (system)
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Frequently Asked Questions

What is Boltzmann’s entropy formula and what does W mean?

Boltzmann’s formula is S = k_B ln(W), where W is the multiplicity (the number of accessible microstates for the macrostate). A larger W means more possible microstates and therefore a larger entropy.

How do I calculate entropy change from two multiplicities?

Use ΔS = k_B ln(W2/W1). If W2 is larger than W1, the logarithm is positive and entropy increases; if W2 is smaller, ΔS is negative.

Why must I use ln instead of log base 10?

The Boltzmann relation is defined with the natural logarithm ln (base e). Using log base 10 would give a numerically different value unless you also convert by the appropriate factor.

How are per-mole entropy values related to the per-system result?

A per-system entropy can be converted to a molar entropy by multiplying by Avogadro’s number: S_m = N_A S and ΔS_m = N_A ΔS. This corresponds to using the gas constant R = N_A k_B in molar forms such as S_m = R ln(W).