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Graph of a Quadratic Function

Consider the following graph of a quadratic function. What are its key features (vertex, axis of symmetry, intercepts, domain, range), and what quadratic equation matches the graph?

Subject: Math Algebra Chapter: Functions Topic: Function Transformer Answer included
consider the following graph of a quadratic function quadratic function graph parabola vertex form axis of symmetry x-intercepts y-intercept domain and range
Accepted answer Answer included

Consider the following graph of a quadratic function. A quadratic function has the form \(y=ax^2+bx+c\) with \(a\neq 0\), and its graph is a parabola whose opening and symmetry are controlled by \(a\) and whose key features include a single vertex and a vertical axis of symmetry.

Assumed plotted features for the shown parabola

The graph below is treated as an upward-opening parabola with x-intercepts at \((-1,0)\) and \((3,0)\) and a lowest point at the vertex \((1,-4)\). These values define a unique quadratic function consistent with the drawing.

Graph of a quadratic function (parabola) A parabola opening upward with vertex at (1, -4), x-intercepts at (-1, 0) and (3, 0), and y-intercept at (0, -3). The axis of symmetry x=1 is shown as a dashed line. x y axis: x = 1 (-1, 0) (3, 0) (1, -4) (0, -3) y = (x - 1)² - 4
The parabola opens upward, reaches its minimum at the vertex \((1,-4)\), crosses the x-axis at \((-1,0)\) and \((3,0)\), and crosses the y-axis at \((0,-3)\). The dashed vertical line shows the axis of symmetry \(x=1\).

Quadratic equation consistent with the graph

The x-intercepts \((-1,0)\) and \((3,0)\) imply a factored form \(y=a(x+1)(x-3)\) for some nonzero constant \(a\). The axis of symmetry for a parabola lies halfway between the roots, giving \(x=\frac{-1+3}{2}=1\), which matches the drawn symmetry line. Substituting the vertex point \((1,-4)\) determines \(a\):

\[ -4 \;=\; a(1+1)(1-3)\;=\;a(2)(-2)\;=\;-4a \quad\Rightarrow\quad a=1. \]

The quadratic function is therefore

\[ y=(x+1)(x-3)=x^2-2x-3. \]

Vertex form and transformation meaning

Completing the square converts the standard form into vertex form, which displays the horizontal and vertical shifts relative to \(y=x^2\):

\[ y=x^2-2x-3 =\bigl(x^2-2x+1\bigr)-1-3 =(x-1)^2-4. \]

The expression \((x-1)^2-4\) indicates a shift right by 1 and down by 4, with no vertical stretch because the leading coefficient is 1.

Domain, range, and monotonic behavior

A quadratic function is defined for every real input, so the domain is all real numbers. The opening direction is upward because \(a=1>0\), so the vertex gives a minimum value. With vertex \(y=-4\), the range is \(y\ge -4\):

\[ \mathrm{Domain}=(-\infty,\infty), \qquad \mathrm{Range}=[-4,\infty). \]

The function decreases on \((-\infty,1]\) and increases on \([1,\infty)\), reflecting symmetry about \(x=1\).

Key features (summary table)

Feature Value Graph interpretation
Equation (vertex form) \(y=(x-1)^2-4\) Vertex at \((1,-4)\) with upward opening
Equation (standard form) \(y=x^2-2x-3\) Expanded from \((x+1)(x-3)\)
Vertex \((1,-4)\) Lowest point of the parabola
Axis of symmetry \(x=1\) Vertical line through the vertex
x-intercepts (zeros) \((-1,0)\), \((3,0)\) Where the graph crosses the x-axis
y-intercept \((0,-3)\) Where the graph crosses the y-axis
Domain \((-\infty,\infty)\) All real inputs are allowed
Range \([-4,\infty)\) Minimum at the vertex with upward opening

Common pitfalls

Range direction errors. An upward-opening parabola has a minimum at the vertex, while a downward-opening parabola has a maximum at the vertex.

Axis placement errors. The symmetry line passes through the vertex and lies midway between the x-intercepts when two real roots exist.

Intercept confusion. The y-intercept corresponds to \(x=0\), while x-intercepts correspond to \(y=0\).

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