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Sodium Hydrogen Sulphate Solution: Ions, Acidity, and pH

What ions are present in sodium hydrogen sulphate solution, why is the solution acidic, and how can its pH be estimated for a 0.100 M solution at 25 °C?

Subject: General Chemistry Chapter: Acid Base Equilibrium Topic: Hydrolysis Answer included
sodium-hydrogen-sulphate-solution sodium hydrogen sulphate solution sodium hydrogen sulfate solution NaHSO4 solution hydrogen sulfate ion acidic salt solution hydronium ion sulfate ion
Accepted answer Answer included

Sodium Hydrogen Sulphate Solution

Sodium hydrogen sulphate solution is an acidic salt solution formed when \(\mathrm{NaHSO_4}\), also called sodium bisulfate or sodium hydrogen sulfate, dissolves in water. The salt separates into \(\mathrm{Na^+}\) and \(\mathrm{HSO_4^-}\), and the hydrogen sulfate ion donates a proton to water, forming hydronium ions.

Salt identity

Sodium hydrogen sulphate has the formula \(\mathrm{NaHSO_4}\). It is not a neutral sulfate salt such as \(\mathrm{Na_2SO_4}\); it still contains an acidic hydrogen in the hydrogen sulfate ion.

Acidic character

The solution is acidic because \(\mathrm{HSO_4^-}\) behaves as a Brønsted-Lowry acid in water and increases the concentration of \(\mathrm{H_3O^+}\).

Ionic composition in water

The dissolution of sodium hydrogen sulphate is represented as:

\[ \mathrm{NaHSO_4}(s) \rightarrow \mathrm{Na^+}(aq) + \mathrm{HSO_4^-}(aq) \]

Sodium ion is a spectator ion in the acid-base behavior of the solution. The chemically important species is \(\mathrm{HSO_4^-}\), which can donate a proton to water:

\[ \mathrm{HSO_4^-}(aq) + \mathrm{H_2O}(l) \rightleftharpoons \mathrm{H_3O^+}(aq) + \mathrm{SO_4^{2-}}(aq) \]
Dissociation and acidic equilibrium in sodium hydrogen sulphate solution The diagram shows sodium hydrogen sulphate dissolving into sodium ions and hydrogen sulfate ions, followed by partial reaction of hydrogen sulfate with water to form hydronium and sulfate ions. Sodium hydrogen sulphate in water NaHSO₄(s) → Na⁺(aq) + HSO₄⁻(aq), followed by acidic equilibrium Solid salt NaHSO₄ ionic compound before dissolving dissolves Na⁺ HSO₄⁻ Na⁺ HSO₄⁻ H₃O⁺ SO₄²⁻ Aqueous solution Na⁺ is spectator; HSO₄⁻ produces H₃O⁺ and SO₄²⁻ Acid equilibrium HSO₄⁻ + H₂O ⇌ H₃O⁺ + SO₄²⁻ hydronium makes the solution acidic pH behavior acidic 0 7 14 0.100 M NaHSO₄ gives pH near 1.5
The diagram separates two processes: complete dissolution of \(\mathrm{NaHSO_4}\) into ions and partial acid dissociation of \(\mathrm{HSO_4^-}\). The production of \(\mathrm{H_3O^+}\) explains why sodium hydrogen sulphate solution has \(\mathrm{pH < 7}\).

Species present in solution

A sodium hydrogen sulphate solution contains several important aqueous species. The relative amounts depend on concentration and temperature, but the qualitative identity of the species is stable: \(\mathrm{Na^+}\), \(\mathrm{HSO_4^-}\), \(\mathrm{H_3O^+}\), \(\mathrm{SO_4^{2-}}\), and water.

Species Role in solution Chemical meaning
\(\mathrm{Na^+}(aq)\) Spectator cation It comes from salt dissociation and does not cause the acidity.
\(\mathrm{HSO_4^-}(aq)\) Acidic anion It donates a proton to water and forms \(\mathrm{H_3O^+}\).
\(\mathrm{H_3O^+}(aq)\) Acidity carrier Its concentration determines the pH of the solution.
\(\mathrm{SO_4^{2-}}(aq)\) Conjugate base It forms when \(\mathrm{HSO_4^-}\) loses a proton.
\(\mathrm{H_2O}(l)\) Solvent and proton acceptor It accepts a proton from \(\mathrm{HSO_4^-}\) to form \(\mathrm{H_3O^+}\).

Acid-base interpretation

Hydrogen sulfate ion is amphiprotic in principle, but in ordinary General Chemistry treatment of sodium hydrogen sulphate solution its acid behavior is dominant. Its acid equilibrium is written as:

\[ K_{a2} = \frac{ [\mathrm{H_3O^+}][\mathrm{SO_4^{2-}}] }{ [\mathrm{HSO_4^-}] } \]

At \(25^\circ\mathrm{C}\), a commonly used value is approximately:

\[ K_{a2} \approx 1.2 \times 10^{-2} \]

The subscript in \(K_{a2}\) reflects the second acid dissociation of sulfuric acid chemistry. Sodium hydrogen sulphate contains \(\mathrm{HSO_4^-}\), which is the species involved in this second dissociation.

pH estimate for a 0.100 M solution

For a quantitative model, the solution is assumed to be \(0.100\ \mathrm{M}\) in \(\mathrm{NaHSO_4}\) at \(25^\circ\mathrm{C}\), and activity effects are ignored. Complete salt dissociation gives an initial hydrogen sulfate concentration of \(0.100\ \mathrm{M}\).

Equilibrium term \(\mathrm{HSO_4^-}\) \(\mathrm{H_3O^+}\) \(\mathrm{SO_4^{2-}}\)
Initial concentration \(0.100\) \(0\) \(0\)
Change \(-x\) \(+x\) \(+x\)
Equilibrium concentration \(0.100-x\) \(x\) \(x\)

Substitution into the acid equilibrium expression gives:

\[ 1.2 \times 10^{-2} = \frac{x^2}{0.100-x} \]

Rearrangement gives a quadratic equation:

\[ x^2 + (1.2 \times 10^{-2})x - (1.2 \times 10^{-3}) = 0 \]

The chemically meaningful positive root is:

\[ x = \frac{ -1.2 \times 10^{-2} + \sqrt{(1.2 \times 10^{-2})^2 + 4(1.2 \times 10^{-2})(0.100)} }{2} \approx 2.9 \times 10^{-2}\ \mathrm{M} \]

Therefore:

\[ [\mathrm{H_3O^+}] \approx 2.9 \times 10^{-2}\ \mathrm{M} \]
\[ \mathrm{pH} = -\log(2.9 \times 10^{-2}) \approx 1.54 \]

Why the solution is not neutral

A neutral salt solution usually comes from a strong acid and a strong base with no acidic or basic ion left to react with water. Sodium hydrogen sulphate solution is different because \(\mathrm{HSO_4^-}\) still contains an ionizable hydrogen. The sodium ion does not neutralize this acidity; it only balances charge in the solid salt and remains hydrated in solution.

Comparison with related sulfate solutions

Solution Main ions after dissolution Acid-base behavior Expected pH trend
\(\mathrm{NaHSO_4}(aq)\) \(\mathrm{Na^+}\), \(\mathrm{HSO_4^-}\) \(\mathrm{HSO_4^-}\) donates a proton to water. Acidic
\(\mathrm{Na_2SO_4}(aq)\) \(\mathrm{Na^+}\), \(\mathrm{SO_4^{2-}}\) \(\mathrm{SO_4^{2-}}\) is a weak base, but the solution is often treated as nearly neutral in introductory contexts. Near neutral to slightly basic
\(\mathrm{H_2SO_4}(aq)\) \(\mathrm{H_3O^+}\), \(\mathrm{HSO_4^-}\), \(\mathrm{SO_4^{2-}}\) The first proton transfer is essentially complete; the second is represented by \(K_{a2}\). Strongly acidic

Laboratory observations

Sodium hydrogen sulphate dissolves to produce a clear aqueous solution. Universal indicator, pH paper, or a calibrated pH electrode would show acidic behavior. No gas evolution or precipitate is expected from simple dissolution in pure water. The important chemical evidence is the low pH caused by hydronium ion formation.

Common pitfalls

Misinterpretation Correction
Sodium hydrogen sulphate solution is neutral because it contains sodium. The acidity comes from \(\mathrm{HSO_4^-}\), not from \(\mathrm{Na^+}\).
\(\mathrm{NaHSO_4}\) remains mostly as neutral formula units in water. The salt dissociates into hydrated ions, mainly \(\mathrm{Na^+}\) and \(\mathrm{HSO_4^-}\).
The equation must show only \(\mathrm{H^+}\) as the acid product. In aqueous acid-base chemistry, \(\mathrm{H_3O^+}\) gives a more accurate representation of proton transfer to water.
The pH of \(0.100\ \mathrm{M}\) \(\mathrm{NaHSO_4}\) equals exactly 1.00. The hydrogen sulfate ion is not fully dissociated in its second proton-transfer equilibrium, so the estimated pH is higher than 1.00.

Sodium hydrogen sulphate solution is best described as an acidic electrolyte solution: \(\mathrm{NaHSO_4}\) dissociates completely as a soluble salt, while \(\mathrm{HSO_4^-}\) only partially donates its proton to water. This distinction explains both the ionic composition and the measured acidity.

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