8. Angle Bisector Theorem Calculator
In a triangle \(ABC\), let \(AD\) be the internal angle bisector of \(\angle A\), meeting the opposite side \(BC\) at \(D\).
The Angle Bisector Theorem relates how the bisector divides the opposite side to the lengths of the adjacent sides.
The theorem
If \(AD\) bisects \(\angle A\), then:
\[
\begin{aligned}
\frac{BD}{DC} &= \frac{AB}{AC}
\end{aligned}
\]
How to solve common unknowns
Depending on what is unknown, rearrange the ratio:
\[
\begin{aligned}
BD &= DC\cdot \frac{AB}{AC} \\
DC &= BD\cdot \frac{AC}{AB} \\
AB &= AC\cdot \frac{BD}{DC} \\
AC &= AB\cdot \frac{DC}{BD}
\end{aligned}
\]
Alternative form: split the whole side \(BC\)
If you know the full opposite side \(BC\) instead of one segment, you can compute both segments directly:
\[
\begin{aligned}
BD &= \frac{AB}{AB+AC}\,BC \\
DC &= \frac{AC}{AB+AC}\,BC
\end{aligned}
\]
Worked example (triangle-feasible)
Given adjacent sides \(AB=7\) cm, \(AC=10\) cm, and one segment \(DC=9\) cm, find the other segment \(BD=x\).
\[
\begin{aligned}
\frac{BD}{DC} &= \frac{AB}{AC} \\
BD &= DC\cdot \frac{AB}{AC} \\
&= 9\cdot \frac{7}{10} \\
&= 6.3\ \text{cm}
\end{aligned}
\]
Consistency check
If all four values are given, the configuration is consistent with an angle bisector when the two ratios match:
\[
\begin{aligned}
\frac{BD}{DC} \stackrel{?}{=} \frac{AB}{AC}
\end{aligned}
\]
Advanced (university): bisector length
If the three side lengths form a feasible triangle, the bisector length \(AD\) can be computed using:
\[
\begin{aligned}
AD^2 &= AB\cdot AC\left(1-\frac{BC^2}{(AB+AC)^2}\right)
\end{aligned}
\]
Common mistakes
- Mixing up which sides are adjacent to the bisected angle (use \(AB\) and \(AC\) for \(\angle A\)).
- Using \(BD/DC = AC/AB\) (the ratio is \(AB/AC\) when bisecting \(\angle A\)).
- Entering negative or zero lengths (segments and sides must be positive).
Tip: the diagram in the calculator places \(D\) using the segments \(BD\) and \(DC\). If the side lengths cannot form a real triangle,
the tool will still compute segment ratios, but the diagram may be shown as “not to scale”.