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Parametric Derivative Calculator

Math Calculus • Parametric Equations and Polar Coordinates

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Compute \(\frac{dy}{dx}\), \(\frac{d^2y}{dx^2}\), and higher-order derivatives from parametric equations. The graph shows the curve, direction arrows, an animated point, and the tangent line at the selected value of \(t\).

First derivative \(\displaystyle \frac{dy}{dx}=\frac{dy/dt}{dx/dt}\) Second derivative \(\displaystyle \frac{d^2y}{dx^2}=\frac{d}{dt}\!\left(\frac{dy}{dx}\right)\Big/\frac{dx}{dt}\) Tangent line \(\displaystyle y-y_0=m(x-x_0)\) Higher order \(\displaystyle y_{[n]}=\frac{d}{dt}(y_{[n-1]})\Big/\frac{dx}{dt}\)

Parametric derivative input

Examples: cos(t), t^2, 1+2t
Examples: sin(t), t^3, 3-t
You may use pi, for example pi/4.
Live setup

Quick examples

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Enter \(x(t)\), \(y(t)\), and \(t_0\), then click “Calculate derivatives”.

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Frequently Asked Questions

How do you find dy/dx for parametric equations?

Use dy/dx = (dy/dt)/(dx/dt), as long as dx/dt is not zero.

How do you find d²y/dx² for parametric equations?

Differentiate dy/dx with respect to t, then divide by dx/dt.

What is dy/dx for x = cos(t), y = sin(t)?

dx/dt = -sin(t), dy/dt = cos(t), so dy/dx = cos(t)/(-sin(t)) = -cot(t).

What happens if dx/dt = 0?

dy/dx may be undefined, and the curve may have a vertical tangent at that parameter value.

What happens if both dx/dt and dy/dt are zero?

The point may be singular, such as a cusp. Ordinary tangent and derivative formulas may need special interpretation.

Can the calculator compute higher derivatives?

Yes. It uses the recurrence y[n] = d/dt(y[n-1]) divided by dx/dt for higher-order parametric derivatives.

Does the calculator show the tangent line?

Yes. It displays the tangent line at the selected t0 value on the curve graph.

Why are direction arrows useful?

They show the orientation of the parametric curve as the parameter t increases.