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Parametric Arc Length Calculator

Math Calculus • Parametric Equations and Polar Coordinates

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Compute the arc length of a parametric curve \(x=x(t)\), \(y=y(t)\). The calculator builds the speed function, tries to recognize an exact form, and falls back to numerical integration when needed.

Parametric speed \(\displaystyle v(t)=\sqrt{\left(x'(t)\right)^2+\left(y'(t)\right)^2}\) Arc length \(\displaystyle L=\int_a^b v(t)\,dt\) Parabola example \(\displaystyle x=t,\ y=t^2\Rightarrow v(t)=\sqrt{1+4t^2}\) Numerical fallback \(\displaystyle L\approx \sum_i \sqrt{(\Delta x_i)^2+(\Delta y_i)^2}\)

Parametric arc length input

Examples: t, cos(t), t - sin(t)
Examples: t^2, sin(t), 1 - cos(t)
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Quick examples

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Enter \(x(t)\), \(y(t)\), and the parameter interval, then click “Calculate arc length”.

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Frequently Asked Questions

What is the arc length formula for a parametric curve?

For x = x(t) and y = y(t), the arc length from t = a to t = b is L = integral from a to b of sqrt((dx/dt)^2 + (dy/dt)^2) dt.

What is the speed function?

The speed function is v(t) = sqrt((x'(t))^2 + (y'(t))^2). Arc length is the integral of speed.

Does the calculator give exact results?

It gives exact results for recognized patterns such as lines, circles with constant radius, and x = t, y = t^2. For other curves, it uses numerical integration.

What is the exact arc length for x = t, y = t^2 from 0 to 3?

The integral is integral from 0 to 3 of sqrt(1 + 4t^2) dt, which equals (3/2)sqrt(37) + (1/4)arsinh(6).

Why is the speed graph useful?

The area under the speed graph v(t) equals the arc length. The shaded area shows accumulated length.

What does the highlighted arc show?

It shows the portion of the parametric curve whose length is being measured.

When should I use numerical integration?

Use numerical integration when the speed function is difficult or impossible to integrate in elementary form.

What is the polyline approximation?

It estimates arc length by connecting sampled points with small straight segments and adding their lengths.