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Freezing Point Depression

General Chemistry • Solutions and Their Physical Properties

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Freezing Point Depression — \( \Delta T_f = i\,K_f\,m \)

For dilute solutions the freezing point depression is \(\displaystyle \Delta T_f = i\,K_f\,m\), where \(i\) is the van ’t Hoff factor (electrolytes), \(K_f\) is the cryoscopic constant of the solvent, and \(m\) is the molality (mol·kg⁻¹). This calculator works with either a direct molality or with mass / molar mass / solvent mass. It can also solve for other variables (e.g., find \(M_r\) from a measured \(\Delta T_f\)).

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Frequently Asked Questions

What is freezing point depression and why does it happen?

Freezing point depression is the decrease in a solvent’s freezing point when a non-volatile solute is dissolved in it. It is a colligative property, meaning it depends mainly on the number of dissolved particles rather than their chemical identity.

How do you calculate freezing point depression using molality?

For dilute solutions, use DeltaTf = i x Kf x m, where i is the van 't Hoff factor, Kf is the solvent’s cryoscopic constant, and m is molality in mol·kg^-1. The calculator applies this relationship and can also rearrange it to solve for an unknown.

What is the difference between molality and molarity in freezing point problems?

Molality is moles of solute per kilogram of solvent, while molarity is moles of solute per liter of solution. Colligative-property equations like DeltaTf = i x Kf x m are written in terms of molality because it uses solvent mass and is less sensitive to temperature-related volume changes.

How can freezing point depression be used to find molar mass?

If DeltaTf is measured experimentally, you can solve for molar mass by combining DeltaTf = i x Kf x m with m = (mass of solute / Mr) / (mass of solvent in kg). The calculator performs this cryoscopy rearrangement when you choose Mr as the unknown.

Is DeltaTf the same in Celsius and Kelvin?

Yes, a temperature difference has the same magnitude in C and K. Only absolute temperatures require conversion, so Tf° and Tf must be in the same unit when computing Tf = Tf° - DeltaTf.