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Molecular Polarity: Determining Polar vs Nonpolar Molecules

For the molecules CO2, H2O, BF3, NH3, CH4, and SO2, which are polar and which are nonpolar, and why?

Subject: General Chemistry Chapter: Chemical Bonds Topic: Lewis Diagrams for Atoms and Simple Ions Answer included
molecular polarity polar molecule nonpolar molecule bond polarity dipole moment electronegativity difference VSEPR geometry symmetry
Accepted answer Answer included

Meaning of molecular polarity

Molecular polarity describes whether a molecule has a nonzero net electric dipole moment. A molecule is polar if the vector sum of its bond dipoles (and any lone-pair contributions to electron density) produces a nonzero net dipole; it is nonpolar if those dipoles cancel by symmetry.

A compact way to express the rule is: \[ \vec{\mu}_{\text{net}} = \sum_i \vec{\mu}_i \] If \(\vec{\mu}_{\text{net}} = \vec{0}\), the molecule is nonpolar; otherwise it is polar.

Reliable procedure for deciding polar vs nonpolar

  1. Draw the correct Lewis structure (connectivity and lone pairs matter).
  2. Determine the molecular geometry (shape), not just electron-domain geometry.
  3. Mark bond dipoles toward the more electronegative atom (direction of electron density shift).
  4. Check symmetry and add vectors: symmetric shapes with identical surrounding atoms often cancel; asymmetric shapes often do not.

Apply the procedure to common molecules

The list below tests molecular polarity using standard shapes and symmetry: CO2, H2O, BF3, NH3, CH4, and SO2.

Molecule Lewis/VSEPR shape (molecular geometry) Are individual bonds polar? Do dipoles cancel? Molecular polarity Key reason
CO2 Linear (O=C=O) Yes (C–O) Yes Nonpolar Two equal C–O dipoles are opposite along a line → net \(\vec{\mu}=\vec{0}\).
H2O Bent (two lone pairs on O) Yes (O–H) No Polar Bent geometry prevents cancellation; dipoles add to a nonzero net dipole.
BF3 Trigonal planar Yes (B–F) Yes Nonpolar Three identical bond dipoles separated by 120° cancel by symmetry.
NH3 Trigonal pyramidal (one lone pair on N) Yes (N–H) No Polar Lone pair makes the shape pyramidal; dipoles do not cancel.
CH4 Tetrahedral Effectively very weak (C–H) Yes Nonpolar Highly symmetric tetrahedral arrangement cancels dipoles (net \(\vec{\mu}=\vec{0}\)).
SO2 Bent (one lone pair on S in a trigonal-planar electron geometry) Yes (S–O) No Polar Bent geometry yields a nonzero vector sum of S–O dipoles.

Visualization: vector cancellation vs non-cancellation

H₂O: bent → polar CO₂: linear → nonpolar O H H ≈ 104.5° δ− δ+ δ+ net \(\vec{\mu}\) ≠ 0 C O O δ− δ− δ+ dipoles cancel → net \(\vec{\mu} = \vec{0}\) 180°
In H2O, the bent shape makes the two O–H dipoles add to a nonzero resultant. In CO2, the linear and symmetric arrangement makes the two C–O dipoles cancel exactly.

Final classification

Molecular polarity is controlled by both bond polarity and geometry: CO2, BF3, and CH4 are nonpolar because symmetry cancels dipoles, while H2O, NH3, and SO2 are polar because their shapes prevent complete cancellation.

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