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Molar mass of glucose
Glucose has the chemical formula C6H12O6, so its molar mass is found by adding the mass contributions from 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms (in g/mol).
1) Identify the atom counts from the formula
From C6H12O6:
- Carbon: 6 atoms
- Hydrogen: 12 atoms
- Oxygen: 6 atoms
2) Use standard atomic masses and compute each contribution
Using common periodic-table values (to typical textbook precision): \( M_\text{C} = 12.01 \), \( M_\text{H} = 1.008 \), \( M_\text{O} = 16.00 \) (all in g/mol).
| Element | Count in C6H12O6 | Atomic mass (g/mol) | Contribution (g/mol) |
|---|---|---|---|
| C | 6 | 12.01 | \(6 \times 12.01 = 72.06\) |
| H | 12 | 1.008 | \(12 \times 1.008 = 12.096\) |
| O | 6 | 16.00 | \(6 \times 16.00 = 96.00\) |
3) Add contributions to obtain the molar mass
\[ M(\text{C}_6\text{H}_{12}\text{O}_6) = (6)(12.01) + (12)(1.008) + (6)(16.00) \]
\[ M = 72.06 + 12.096 + 96.00 = 180.156 \text{ g/mol} \approx 180.16 \text{ g/mol} \]
Minor differences (e.g., 180.15 vs 180.16 g/mol) occur depending on whether oxygen is taken as 15.999 g/mol and how many decimals are kept in the atomic masses.
Visualization: how each element contributes to the molar mass
Final result
The molar mass of glucose is \(\boxed{180.16\ \text{g/mol}}\) (to two decimal places).
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