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How Many Grams Is Silver Nitrate? (AgNO3 Molar Mass)

How many grams is silver nitrate (AgNO3), and how is its mass found from a given amount in moles?

Subject: General Chemistry Chapter: Chemical Compounds Topic: Molecular Mass and Formula Mass Answer included
how many grams is silver nitrate silver nitrate molar mass AgNO3 molar mass formula mass grams per mole mole to grams conversion atomic mass stoichiometry
Accepted answer Answer included

How many grams is silver nitrate?

The wording “how many grams is silver nitrate” is naturally interpreted in general chemistry as the mass of 1 mole of silver nitrate, AgNO3. That quantity is the molar mass (formula mass) expressed in g/mol.

Chemical identity and counting atoms

Silver nitrate has the formula AgNO3, which encodes the atom count in one formula unit:

  • Silver, Ag: 1 atom
  • Nitrogen, N: 1 atom
  • Oxygen, O: 3 atoms

Molar mass and the gram–mole connection

The molar mass \(M\) of a compound is the sum of the atomic masses of its constituent atoms, scaled by their subscripts. It links amount \(n\) (in moles) to mass \(m\) (in grams) by:

\[ m = n \cdot M \]

Molar-mass calculation for AgNO3

Using standard average atomic masses (periodic-table values; slight rounding differences exist across tables), the molar mass is:

\[ M(\mathrm{AgNO_3}) = M(\mathrm{Ag}) + M(\mathrm{N}) + 3\,M(\mathrm{O}) \]
Element Count Atomic mass (g/mol) Contribution (g/mol)
Ag 1 107.8682 \(1 \cdot 107.8682 = 107.8682\)
N 1 14.0067 \(1 \cdot 14.0067 = 14.0067\)
O 3 15.999 \(3 \cdot 15.999 = 47.997\)
Total \(107.8682 + 14.0067 + 47.997 = 169.8719\)

Rounded to typical significant figures for general chemistry, \(M(\mathrm{AgNO_3}) \approx 169.87\ \mathrm{g/mol}\). This also means 1 mol of silver nitrate has a mass of about 169.87 g.

Common conversions involving silver nitrate

Any mole-to-gram conversion for AgNO3 uses \(M = 169.87\ \mathrm{g/mol}\) (or the locally adopted table value). Representative examples:

  • \(n = 0.250\ \mathrm{mol}\): \(m = 0.250 \cdot 169.87 \approx 42.47\ \mathrm{g}\)
  • \(n = 0.100\ \mathrm{mol}\): \(m = 0.100 \cdot 169.87 \approx 16.99\ \mathrm{g}\)
  • \(m = 25.0\ \mathrm{g}\): \(n = \dfrac{25.0}{169.87} \approx 0.147\ \mathrm{mol}\)

Mass composition visualization

AgNO3 molar-mass composition A stacked bar shows how silver, nitrogen, and oxygen contribute to the molar mass of AgNO3. A second cue links 1 mol to approximately 169.87 grams. AgNO3 molar mass ≈ 169.87 g/mol Stacked bar segments represent mass contributions from each element in one formula unit. Ag: 107.8682 N: 14.0067 O3: 47.997 Amount–mass link (silver nitrate) 1 mol AgNO3 ≈ 169.87 g Any mass of AgNO3 follows \(m = n \cdot 169.87\).
The bar partitions the molar mass of AgNO3 into its element-by-element mass contributions. Silver contributes the largest share because its atomic mass dominates the formula mass.

Common pitfalls

  • Confusion between grams of AgNO3 and grams of elemental silver; the compound includes nitrate mass.
  • Oxygen subscript omission; AgNO3 contains three oxygen atoms, contributing nearly 48 g/mol.
  • Minor numerical differences across periodic tables; consistent rounding within one dataset keeps stoichiometry coherent.
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