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Ferric Chloride (FeCl3): Name, Formula, Oxidation State, and Molar Mass

What is ferric chloride, and how are its formula, ion charges, oxidation state, and molar mass determined from its name?

Subject: General Chemistry Chapter: Chemical Compounds Topic: Naming Binary Compounds of Metals and Nonmetals Answer included
ferric chloride iron(III) chloride FeCl3 ionic compound oxidation state valence formula from name molar mass
Accepted answer Answer included

Ferric chloride is the classical (older) name for iron(III) chloride, an ionic compound composed of iron cations and chloride anions. The word “ferric” indicates iron in the \(+3\) oxidation state, distinguishing it from “ferrous” compounds where iron is \(+2\).

Step 1: Decode the name into ions and charges

“Chloride” indicates the anion \( \mathrm{Cl^-} \). “Ferric” indicates the cation \( \mathrm{Fe^{3+}} \) (iron(III)).

Naming equivalence: ferric chloride and iron(III) chloride refer to the same compound; the Roman numeral explicitly states the iron oxidation state.

Step 2: Write the formula by charge balance

An electrically neutral ionic formula requires total positive charge to equal total negative charge. One \( \mathrm{Fe^{3+}} \) requires three \( \mathrm{Cl^-} \) ions:

\[ \mathrm{Fe^{3+}} + 3\,\mathrm{Cl^-} \;\longrightarrow\; \mathrm{FeCl_3} \]

The simplest whole-number ratio of ions is therefore \(1:3\), giving the formula \( \mathrm{FeCl_3} \).

Cl Cl Cl Fe 3+ Charge Balance: (+3) + 3 × (−1) = 0
Ion-ratio diagram for ferric chloride: one \( \mathrm{Fe^{3+}} \) is balanced by three \( \mathrm{Cl^-} \), producing the neutral formula \( \mathrm{FeCl_3} \).

Step 3: Confirm the oxidation state of iron

Chlorine in chloride is \( -1 \). For a neutral compound \( \mathrm{FeCl_3} \), the iron oxidation state \(x\) satisfies:

\[ x + 3(-1) = 0 \quad \Rightarrow \quad x = +3 \]

This matches the “ferric” (iron(III)) designation.

Step 4: Dissociation in water (electrolyte view)

In an aqueous-solution model used in general chemistry, ferric chloride is treated as a strong electrolyte that separates into ions:

\[ \mathrm{FeCl_3(s)} \;\longrightarrow\; \mathrm{Fe^{3+}(aq)} + 3\,\mathrm{Cl^-(aq)} \]

The stoichiometric ion ratio matters in solution calculations: 1 mole of \( \mathrm{FeCl_3} \) produces 1 mole of \( \mathrm{Fe^{3+}} \) and 3 moles of \( \mathrm{Cl^-} \).

Step 5: Molar mass and percent composition

Using standard atomic masses \(M(\mathrm{Fe}) = 55.845\ \mathrm{g\cdot mol^{-1}}\) and \(M(\mathrm{Cl}) = 35.45\ \mathrm{g\cdot mol^{-1}}\), the molar mass of ferric chloride is:

\[ M(\mathrm{FeCl_3}) = 55.845 + 3(35.45) = 55.845 + 106.35 = 162.195\ \mathrm{g\cdot mol^{-1}} \]

Quantity Result for ferric chloride How it is obtained
Common name Ferric chloride Classical naming; “ferric” = iron(III)
Stock/IUPAC-style name Iron(III) chloride Roman numeral gives oxidation state
Formula \(\mathrm{FeCl_3}\) Charge balance: \(+3\) with \(3 \times (-1)\)
Ions in water \(\mathrm{Fe^{3+}}\) and \(3\,\mathrm{Cl^-}\) Dissociation stoichiometry
Molar mass \(162.195\ \mathrm{g\cdot mol^{-1}}\) \(55.845 + 3(35.45)\)

Percent by mass follows directly from the molar-mass parts:

\[ \%\mathrm{Fe} = \frac{55.845}{162.195}\times 100 = 34.43\% \qquad \%\mathrm{Cl} = \frac{106.35}{162.195}\times 100 = 65.57\% \]

One quick stoichiometry check

If \(n\) moles of ferric chloride dissolve, the moles of chloride ions produced are \(3n\). For example, for \(0.250\ \mathrm{mol}\) of ferric chloride:

\[ n(\mathrm{Cl^-}) = 3(0.250) = 0.750\ \mathrm{mol} \] \[ m(\mathrm{FeCl_3}) = 0.250 \times 162.195 = 40.54875\ \mathrm{g} \]

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