Slide presentation
Density of Irregular Solids
General Chemistry • Matter, Its Properties, and Measurement
Matter, properties, and measurement
Irregular solids need displacement to reveal their volume
A cube or cylinder can be measured with a ruler, but a rock, metal fragment, or unknown solid often has no simple geometric formula. Water displacement lets the object’s volume be measured directly.
Learning target
- Use mass and displaced volume to calculate density.
- Explain how water displacement measures irregular volume.
- Connect laboratory readings to \(d = m/V\).
- Evaluate accuracy, units, and significant figures.
Why it matters
Water displacement makes real lab objects measurable
Many solid samples in chemistry are not perfect blocks or spheres. Displacement is useful because it turns an irregular shape into a measurable volume change in a graduated cylinder.
Compare unknown solids
A measured density can help compare an unknown solid with possible materials such as metals, minerals, or plastics.
Use readings correctly
The method requires careful initial and final volume readings, plus correct subtraction.
Evaluate accuracy
Air bubbles, splashing, parallax, and incomplete submersion can change the displaced volume.
Irregular shape
No simple length × width × height formula applies.
Water displacement
The volume of water displaced equals the object’s volume.
Core concept
The object’s volume equals the rise in water level
When a solid is fully submerged and does not dissolve or react, it pushes water out of the space it occupies. The increase in measured water volume is the volume of the solid.
Displacement relationship
The displaced volume is found by subtracting the initial water volume from the final water volume.
Once the volume is known, density can be calculated using the measured mass of the solid.
Vocabulary and units
Every density measurement needs mass, volume, and units
The water displacement method combines a balance reading with two graduated-cylinder readings.
| Quantity or term | Meaning | Common units | Laboratory note |
|---|---|---|---|
| Mass, \(m\) | Amount of matter in the irregular solid. | g | Measure on a balance before placing the solid into water. |
| Initial volume, \(V_{\text{initial}}\) | Water volume before the solid is added. | mL | Read the bottom of the meniscus at eye level. |
| Final volume, \(V_{\text{final}}\) | Water volume after the solid is fully submerged. | mL | Make sure the object is completely underwater and no water is lost. |
| Displaced volume | The volume of the irregular solid. | mL or cm3 | For water displacement, \(1\ \text{mL} = 1\ \text{cm}^{3}\). |
Unit habit
If mass is measured in grams and displaced volume in milliliters, the density unit is g/mL. For solids, g/cm3 is equivalent when volume is from water displacement.
Main relationship
Density uses the displaced volume, not the final water volume
The final cylinder reading includes the original water and the object’s volume. The object’s volume is only the difference between final and initial readings.
Density of an irregular solid
\(m\) comes from the balance.
\(V_{\text{solid}} = V_{\text{final}} - V_{\text{initial}}\)
\(d = m/V_{\text{solid}}\)
Use displaced volume
If water rises from 40.0 mL to 47.2 mL, the solid’s volume is 7.2 mL.
Do not use total final volume
The final reading is not the solid’s volume. It includes the starting water plus the solid.
Interactive displacement model
Adjust mass and water displacement to calculate density
Move the sliders. The cylinder shows initial water level, final water level, displaced volume, and the resulting density.
The solid displaces 7.2 mL of water, so a 54.0 g sample has a density of 7.50 g/mL.
Dynamic relationship
For a fixed mass, larger displaced volume means lower density
If two irregular objects have the same mass, the one that displaces more water has a larger volume and therefore a lower density.
Choose the fixed mass
For a 50 g object, density decreases as displaced volume increases because the same mass occupies more space.
Worked example
Calculate density from water displacement
An irregular metal sample has a mass of \(54.0\ \text{g}\). A graduated cylinder initially contains \(40.0\ \text{mL}\) of water. After the metal is submerged, the final volume is \(47.2\ \text{mL}\). Find the density.
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Identify the mass.
The balance gives \(m = 54.0\ \text{g}\).
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Find the displaced volume.
\(V_{\text{solid}} = V_{\text{final}} - V_{\text{initial}} = 47.2\ \text{mL} - 40.0\ \text{mL} = 7.2\ \text{mL}\).
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Use the density formula.
\(d = m/V = 54.0\ \text{g} / 7.2\ \text{mL}\).
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Calculate the density.
\(d = 7.5\ \text{g/mL}\).
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Check significant figures.
The displaced volume has 2 significant figures, so the final density should be reported with 2 significant figures.
Final answer
The density of the irregular metal sample is \(7.5\ \text{g/mL}\), equivalent to \(7.5\ \text{g/cm}^{3}\).
Common misconception
The final cylinder reading is not the solid’s volume
A frequent error is to divide mass by the final water reading. That gives a density that is too small because the final reading includes water that was already in the cylinder.
Mistake
“The final reading is \(47.2\ \text{mL}\), so the object’s volume is \(47.2\ \text{mL}\).”
Correction
The object’s volume is the increase in water level: \(47.2\ \text{mL} - 40.0\ \text{mL} = 7.2\ \text{mL}\).
Practice check
Use displacement to calculate density
A small irregular solid has a mass of \(32.6\ \text{g}\). The water level in a graduated cylinder rises from \(28.4\ \text{mL}\) to \(34.1\ \text{mL}\) when the object is fully submerged.
Question
What is the volume of the solid, and what is its density? Report the density with the correct significant figures.
Show answer
Displaced volume: \(34.1\ \text{mL} - 28.4\ \text{mL} = 5.7\ \text{mL}\).
Density: \(d = 32.6\ \text{g} / 5.7\ \text{mL} = 5.719...\ \text{g/mL}\).
The displaced volume has 2 significant figures, so the density is \(5.7\ \text{g/mL}\).
Reasoning check
The density is greater than water’s density, so this solid would be expected to sink if it does not trap air and does not react with water.
Apply the topic
Use displacement reasoning before calculating
A strong solution explains how the volume was found, not only how the density was calculated. Always identify whether the volume came from geometry or water displacement.
Calculate density using mass, initial volume, final volume, and displaced volume.
Practice questions Density of Irregular Solids QuestionsPractice displacement, units, significant figures, and lab-measurement reasoning.
How to apply this topic
Measure mass first. Read the initial water volume. Submerge the object completely. Read the final volume. Subtract to find object volume. Then calculate density and check units.
Final summary
The essential takeaways
Water displacement finds volume when geometry formulas are not practical.
Use \(V_{\text{solid}} = V_{\text{final}} - V_{\text{initial}}\).
Use \(d = m/V\), where \(V\) is the solid’s displaced volume.
For water displacement, mL and cm3 are equivalent volume units.
Avoid parallax, air bubbles, splashing, and incomplete submersion.
Significant figures in the final density come from the limiting measurement.