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Hypothesis Tests About μ, σ Not Known, the Critical Value Approach

Statistics • Hypothesis Tests About the Mean and Proportion

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Hypothesis Tests About a Mean: σ Not Known — Critical-Value Approach

Perform a one-sample t test when the population standard deviation σ is unknown. Choose the tail (two/left/right), set α, compute the t statistic, find critical t value(s), and decide: reject or do not reject H0.

Use a t distribution with df = n − 1. With small n, results are most reliable when the population is approximately normal.

Quick reference: tails, df, and rejection rules
Tail H1 sign df Critical value(s) Reject H0 if…
Two-tailed n − 1 ± tα/2, df |t| ≥ tα/2, df
Left-tailed < n − 1 tα, df (negative) t ≤ tα, df
Right-tailed > n − 1 t1−α, df (positive) t ≥ t1−α, df

Decisions are stated as reject H0 or do not reject H0.

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Frequently Asked Questions

How do you run a hypothesis test for a mean when sigma is not known using the critical value approach?

Compute t = (xbar - mu0) / (s / sqrt(n)) and df = n - 1, then find the critical t cutoff(s) from alpha and the tail type. Reject H0 if the observed t is in the rejection region defined by the critical value(s).

What is the difference between the t test and the z test for a mean?

A z test assumes the population standard deviation sigma is known, while a t test uses the sample standard deviation s when sigma is unknown. The t distribution has heavier tails, especially for small df, reflecting additional uncertainty.

How do critical t values work for two-tailed versus one-tailed tests?

For a two-tailed test, the rejection region is split into alpha/2 in each tail, producing ±t(1 - alpha/2, df). For a one-tailed test, all alpha is placed in one tail, producing a single cutoff t(1 - alpha, df) or t(alpha, df) depending on direction.

What assumptions are needed for a one-sample t test?

The test assumes the sample is random and independent and that the population distribution is approximately normal for small samples. For larger n, the sampling distribution of xbar becomes more stable due to the central limit theorem.

Why is degrees of freedom equal to n minus 1 in this calculator?

In a one-sample t procedure, df = n - 1 because one parameter (the sample mean) is estimated from the data when computing the sample standard deviation. This affects the shape of the t distribution used for critical values.