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Michelson Interferometer Fringe Shift Tool

Physics Optics • Wave Nature of Light Interference

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Compute the fringe shift produced by moving one Michelson interferometer mirror, using the round-trip path change \(2\Delta L\). The animation shows the source, beam splitter, fixed mirror, movable mirror, and the fringe pattern at the detector.

Inputs
This tool uses the standard Michelson result \(\Delta m = \dfrac{2\Delta L}{\lambda}\), because moving one mirror by \(\Delta L\) changes that arm’s optical path by \(2\Delta L\). The detector preview uses the normalized two-beam intensity \(I/I_0 = \tfrac12\left(1+V\cos\Delta\phi\right)\), with \(\Delta\phi = \dfrac{4\pi\Delta L}{\lambda}\).
Animation
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Animated Michelson interferometer diagram
The source beam reaches the beam splitter, travels to the fixed and movable mirrors, returns, and recombines at the detector. The fringe panel shows how the pattern shifts as the mirror displacement increases.
Drag to pan. Use the mouse wheel to zoom. Fit view restores the default framing.
Enter values and click “Calculate”.

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Frequently Asked Questions

Why does the formula use 2ΔL instead of just ΔL?

Because the light travels to the movable mirror and then back from it, so the optical path change is twice the physical mirror displacement.

What does Δm = 1 mean physically?

It means one complete fringe crosses the chosen reference point as the mirror moves by the specified amount.

Why can a half-fringe shift change bright to dark?

Because a half-fringe shift corresponds to a phase change of π, which reverses a constructive condition into a destructive one, or vice versa.

What does the visibility parameter do?

It controls the contrast of the fringes. When V = 1 the fringes have maximum contrast, while smaller V values make the bright and dark fringes less distinct.