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Stokes Vector Analyzer

Physics Optics • Diffraction and Polarization

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Convert a polarization state into Stokes parameters \((I,Q,U,V)\), compute the degree of polarization \(\mathrm{DOP}=\sqrt{Q^2+U^2+V^2}/I\), and preview the state through the polarization ellipse and a Poincaré-style projection.

Input mode
Ellipse input
From a Jones vector \(\mathbf{E}=[E_x,E_y]^T\), this calculator uses \(I=|E_x|^2+|E_y|^2\), \(Q=|E_x|^2-|E_y|^2\), \(U=2\operatorname{Re}(E_xE_y^\*)\), \(V=-2\operatorname{Im}(E_xE_y^\*)\). From ellipse input, it uses \(Q=I\cos 2\chi\cos 2\psi\), \(U=I\cos 2\chi\sin 2\psi\), \(V=I\sin 2\chi\).
Animation
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Interactive Stokes-state preview
The left panel shows the polarization ellipse. The middle panel shows normalized Stokes bars. The right panel shows a Poincaré-style projection using \((q,u)\) with color indicating \(v\).
Drag to pan. Use the mouse wheel to zoom. Fit view restores the default framing. Positive \(V\) is labeled right-handed/right-circular in this tool.
Enter values and click “Calculate”.

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Frequently Asked Questions

What do the four Stokes parameters mean?

I is total intensity, Q measures horizontal versus vertical linear polarization, U measures +45° versus -45° linear polarization, and V measures the circular component under the stated sign convention.

Why is the degree of polarization useful?

It tells you how much of the total light is polarized. A value of 1 means fully polarized light, while 0 means completely unpolarized light.

Why can the Stokes formalism describe partially polarized light while Jones vectors cannot?

Because Stokes parameters are real intensity-based quantities that remain meaningful for mixtures and incoherent states, while Jones vectors require a fully coherent, fully polarized field.

How does this calculator define the sign of V?

In this tool, positive V is labeled right-handed or right-circular. Polarization sign conventions can vary across sources, so the chosen convention is stated explicitly.