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Distance Between Atoms in a Molecule

Physics Classical Mechanics • Work Energy and Power

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Calculate the equilibrium distance between atoms using the Lennard-Jones \(6\text{-}12\) potential, evaluate \(U(r)\), estimate the force at a chosen separation, and visualize the molecular potential well.

Graph and output settings

The graph uses the dimensionless curve \(U/\varepsilon\) versus \(r/\sigma\), so the equilibrium point always appears at \(r/\sigma=2^{1/6}\).

Lennard-Jones potential: \[ U(r)=4\varepsilon\left[\left(\frac{\sigma}{r}\right)^{12}-\left(\frac{\sigma}{r}\right)^6\right]. \] Equilibrium separation: \[ r_{\mathrm{eq}}=2^{1/6}\sigma,\qquad U_{\min}=-\varepsilon. \]
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Enter \(\sigma\), \(\varepsilon\), and optionally \(r\), then click “Calculate”.

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Frequently Asked Questions

What is the Lennard-Jones potential?

The Lennard-Jones potential is U(r) = 4 epsilon [(sigma/r)^12 - (sigma/r)^6]. It models short-range repulsion and longer-range attraction between neutral atoms or molecules.

How do you find the equilibrium distance between atoms?

Set dU/dr = 0 for the Lennard-Jones potential. This gives r_eq = 2^(1/6) sigma, which is approximately 1.122 sigma.

What is the potential energy at equilibrium?

At the equilibrium distance, the Lennard-Jones potential reaches its minimum value U_min = -epsilon.

Is sigma the equilibrium distance?

No. Sigma is where U(r) = 0. The equilibrium distance is r_eq = 2^(1/6) sigma, which is slightly larger than sigma.

What does epsilon mean?

Epsilon is the well depth. It is the magnitude of the minimum potential energy, so U_min = -epsilon.

What happens when r is less than r_eq?

The atoms are on the repulsive side of the potential. The force pushes them apart because the short-range repulsive term dominates.

What happens when r is greater than r_eq?

The atoms are on the attractive side of the potential. The force pulls them together because the attractive term dominates.

Why plot U/epsilon versus r/sigma?

Scaling by epsilon and sigma gives a dimensionless curve with the same shape for all Lennard-Jones atom pairs. The equilibrium point is always at r/sigma = 2^(1/6).

What is the radial force formula for the Lennard-Jones potential?

The radial force is F(r) = 24 epsilon / r [2(sigma/r)^12 - (sigma/r)^6], using the sign convention where positive means repulsive.

What is the sample result for sigma = 0.263 nm and epsilon = 1.51e-22 J?

The equilibrium distance is r_eq = 2^(1/6) sigma ≈ 0.295 nm, and the minimum potential energy is U_min = -1.51e-22 J.