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Time Dilation and Length Contraction Tool

Modern Physics • Special Relativity

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Compute relativistic time dilation and length contraction from the Lorentz factor, compare proper and observed quantities, and visualize the result with a clock-comparison animation.

Inputs
The calculator uses \[ \begin{aligned} \gamma &= \frac{1}{\sqrt{1-\beta^2}}, \\ \Delta t &= \gamma \Delta t_0, \\ L &= \frac{L_0}{\gamma}. \end{aligned} \] Here \(\Delta t_0\) is the proper time measured in the rest frame of the clock, and \(L_0\) is the proper length measured in the rest frame of the object.
Animation controls
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Clock comparison animation
The upper panel compares an Earth-frame clock with a moving clock. The lower panel compares a proper rod length with its contracted length, and the side strip summarizes the traveler-versus-lab elapsed times.
Drag to pan. Use the mouse wheel to zoom. The animation shows that the moving clock accumulates less proper time over the same Earth-frame interval, while the moving rod appears shorter along the direction of motion.
Enter values and click “Calculate”.

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Frequently Asked Questions

What is the difference between proper time and dilated time?

Proper time is measured by a clock at rest with the process being observed. Dilated time is the longer interval measured in a frame where that clock is moving, and it is given by delta t = gamma x delta t0.

What is proper length in special relativity?

Proper length is the length of an object measured in the frame where the object is at rest. An observer who sees the object moving measures a shorter length along the direction of motion, given by L = L0 / gamma.

Why do fast muons live longer in the Earth frame?

Their proper lifetime is unchanged in the muon rest frame, but the Earth frame measures a dilated lifetime because the muon is moving very fast. This makes the observed lifetime gamma times larger than the proper lifetime.

Does the twin paradox mean both twins should age less?

Not in the full round-trip situation. A complete twin paradox analysis includes the turnaround and the change of inertial frame, so the situation is not symmetric in the same way as a single constant-speed leg.