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Fine Structure Splitting Estimator

Modern Physics • Atomic and Molecular Physics

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Estimate fine-structure energy splitting for hydrogen-like atoms using a simple relativistic spin-orbit scale. Preview the unsplit level, the split doublet, and the order of the correction across different principal quantum numbers.

Inputs

This estimator uses the hydrogen-like level energy

\[ \begin{aligned} E_n &= -\frac{13.6 Z^2}{n^2}\ \mathrm{eV} \end{aligned} \]

and a simple fine-structure order estimate for the doublet scale

\[ \begin{aligned} \Delta E_{\mathrm{fs}} &\approx \frac{(Z\alpha)^2\,|E_n|}{2n} = \frac{13.6\,\alpha^2 Z^4}{2n^3}\ \mathrm{eV}. \end{aligned} \]

The preview then places two split components around the unsplit level:

\[ \begin{aligned} E_{\pm} &= E_n \pm \frac{\Delta E_{\mathrm{fs}}}{2}. \end{aligned} \]
Animation and diagram controls
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Level-splitting preview and spectral doublet
The left panel shows the unsplit hydrogen-like level and the split fine-structure doublet for the selected \(n\). The right panel shows the corresponding spectral-line doublet as an offset energy preview around an unsplit central line.
Mouse-wheel zoom affects only the hovered panel. Drag inside a panel to pan it independently.
Enter values and click “Calculate”.

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Frequently Asked Questions

What formula does this calculator use for the fine-structure splitting?

It uses a simple estimator of the form Delta E_fs approximately equal to (Z alpha)^2 times the magnitude of E_n divided by 2n. This gives the order of the spin-orbit and relativistic splitting scale for a hydrogen-like level.

Why does the splitting get smaller for larger n?

Because this estimator scales like 1 over n cubed. Higher principal levels are less tightly bound, so their fine-structure splitting is much smaller.

Why does the splitting grow quickly with Z?

Because the estimate scales like Z to the fourth power after combining the hydrogen-like level energy with the relativistic correction factor. Heavier hydrogen-like ions therefore show much larger fine-structure splittings.

Does this include the Lamb shift or exact j-dependent formulas?

No. This calculator is an introductory estimator that gives the approximate size of the fine-structure separation. Exact relativistic spectroscopy requires more detailed formulas and may also include the Lamb shift.