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Conic Section Directrix Finder

Math Geometry • Circles and Conics

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Find the directrix of a parabola or hyperbola from standard parameters. The graph is interactive: drag to pan, wheel/trackpad to zoom, pinch on touch.

Inputs accept 1e-3, pi, e, sqrt(2), sin(), cos(), tan(), ln(), log(), abs(). Use * for multiplication.

Conic type

Vertical: \((x-h)^2=4p(y-k)\). Horizontal: \((y-k)^2=4p(x-h)\).

Vertical vertex form: \(y=a(x-h)^2+k\) with \(a=\frac{1}{4p}\). Horizontal: \(x=a(y-k)^2+h\).

Horizontal: \(\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1\). Vertical: \(\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1\).

Inputs

\(p\) is signed: \(p>0\) opens up/right and \(p<0\) opens down/left.

Uses \(p=\dfrac{1}{4a}\). (So \(a\neq 0\).)

Graph options

The plot uses square units and keeps tick numbers near their axes.

Ready
Choose a shape and click Calculate.
Directrix diagram (square units • pan/zoom enabled)

Drag to pan • wheel/trackpad to zoom • pinch on touch • “Reset view” fits the geometry.

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Frequently Asked Questions

What is the directrix of a conic section?

A directrix is a fixed line used with a focus to define a conic via a distance ratio. Points on the conic satisfy distance-to-focus / distance-to-directrix = e, where e is the eccentricity.

How do you find the directrix of a parabola in standard form?

For (x - h)^2 = 4p(y - k), the directrix is y = k - p. For (y - k)^2 = 4p(x - h), the directrix is x = h - p.

How do you find the directrices of an ellipse from a and b?

For an ellipse (x - h)^2/a^2 + (y - k)^2/b^2 = 1 with a >= b, compute c = sqrt(a^2 - b^2) and e = c/a. If the major axis is horizontal, directrices are x = h ± a/e; if vertical, directrices are y = k ± a/e.

How do you find the directrices of a hyperbola from a and b?

For a hyperbola (x - h)^2/a^2 - (y - k)^2/b^2 = 1, compute c = sqrt(a^2 + b^2) and e = c/a. If the transverse axis is horizontal, directrices are x = h ± a/e; if vertical, directrices are y = k ± a/e.