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Business and Economics Optimization Calculator

Math Calculus • Applications of Derivatives

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Optimize business and economics functions using marginal analysis. Enter cost and revenue functions, choose the objective, and compare endpoints with interior critical points. The graph highlights the optimal production level and shows cost, revenue, profit, and marginal behavior.

Profit \(\displaystyle P(x)=R(x)-C(x)\) Marginal profit \(\displaystyle P'(x)=R'(x)-C'(x)\) Profit maximum \(\displaystyle MR=MC\) Average cost \(\displaystyle AC(x)=\frac{C(x)}{x}\)

Cost, revenue, and optimization interval

Enter \(C(x)\) and \(R(x)\), where \(x\) is quantity produced or sold. The calculator builds \(P(x)=R(x)-C(x)\), checks marginal conditions, and searches for the best value on the interval.

Supported syntax: +, -, *, /, ^, parentheses, x, pi, e, sin, cos, tan, ln, log, sqrt, abs, and exp. Implicit multiplication such as 50x and (x+1)(x-1) is allowed.
Used for marginal and elasticity interpretation.
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\[C(x)=x^2+10x,\qquad R(x)=50x-x^2\]

Graph and output settings

Quick examples

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Enter cost and revenue functions, then click “Optimize”.

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Frequently Asked Questions

How do you maximize profit?

Build the profit function P(x)=R(x)-C(x), find critical points where P'(x)=0, evaluate endpoints and critical points, and choose the largest profit value.

What does MR=MC mean?

MR=MC means marginal revenue equals marginal cost. At an interior profit maximum, this is the usual marginal condition.

What is marginal cost?

Marginal cost is C'(x), the approximate extra cost of producing one more unit.

What is marginal revenue?

Marginal revenue is R'(x), the approximate extra revenue from selling one more unit.

What is marginal profit?

Marginal profit is P'(x)=R'(x)-C'(x). It measures how profit changes when quantity increases.

What is average cost?

Average cost is AC(x)=C(x)/x, the cost per unit produced.

Can the calculator estimate elasticity?

Yes. If price can be approximated by p(x)=R(x)/x, then elasticity is estimated as E=-p/(x p'), when defined.

For C(x)=x^2+10x and R(x)=50x-x^2, where is profit maximized?

Profit is P(x)=40x-2x^2, so P'(x)=40-4x. The interior maximum occurs at x=10, with profit P(10)=200.

How can I get a profit maximum at x=20?

One example is C(x)=x^2+10x and R(x)=90x-x^2. Then P(x)=80x-2x^2 and P'(x)=80-4x, so the maximum occurs at x=20.