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Solving Basic Trigonometric Equations

Math Algebra • Trigonometry Basics

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Solve basic trigonometric equations such as \(2\cos x=\sqrt2\), \(\sin x=\frac12\), \(\cos(2x)=0.5\), and \(\tan(x-\pi/4)=1\). The calculator gives both the general solution and all solutions inside a chosen interval.

Sine equation \(\sin u=k\Rightarrow u=\alpha+2\pi n\) or \(u=\pi-\alpha+2\pi n\) Cosine equation \(\cos u=k\Rightarrow u=\pm\alpha+2\pi n\) Tangent equation \(\tan u=k\Rightarrow u=\alpha+\pi n\) Transformation \(A\,f(Bx-C)+D=K\)

Equation input

Supported form: \(A\sin(Bx-C)+D=K\), \(A\cos(Bx-C)+D=K\), or \(A\tan(Bx-C)+D=K\).

Example: \(2\cos x=\sqrt2\Rightarrow \cos x=\dfrac{\sqrt2}{2}\). On \([0,2\pi]\), the solutions are \(x=\dfrac{\pi}{4}\) and \(x=\dfrac{7\pi}{4}\).

Graph and output settings

Smaller values make the graph scan slower.

Quick examples

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Enter a trigonometric equation, then click “Solve equation”.

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Frequently Asked Questions

How do I solve 2cos x = sqrt(2) on [0, 2pi]?

Divide by 2 to get cos x = sqrt(2)/2. The solutions in [0, 2pi] are x = pi/4 and x = 7pi/4.

Why do sine and cosine often have two solutions?

On the unit circle, most sine and cosine values occur in two quadrants during one full cycle.

Why does tangent use pi instead of 2pi?

Tangent repeats every pi, so tan u = k has general solution u = arctan(k) + pi n.

Can sine or cosine equations have no solution?

Yes. Equations such as sin x = 2 or cos x = -1.5 have no real solution because sine and cosine values must lie between -1 and 1.

Does the calculator handle cos(2x)=0.5?

Yes. It solves for the argument 2x first and then divides by 2 to find x-values in the selected interval.

Can I use open intervals?

Yes. Choose the endpoint type to exclude or include interval endpoints.

Can I export the solutions?

Yes. Use Download CSV to export the equation, general solution, interval, and solution table.