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Powers and Roots of Complex Numbers

Math Algebra • Complex Numbers

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Compute powers and roots of complex numbers using De Moivre’s theorem. Enter a complex number, choose integer power, \(n\)-th roots, or rational power, and view all resulting values on the complex plane.

Polar form \(z=re^{i\theta}\) Integer power \(z^m=r^m e^{im\theta}\) \(n\)-th roots \(\displaystyle w_k=r^{1/n}e^{i(\theta+2\pi k)/n}\) Rational power \(\displaystyle z^{p/q}:\ w_k^q=z^p\)

Input and operation

Supports \(i\), \(\pi\), \(e\), parentheses, \(+\), \(-\), \(*\), \(/\), and integer powers. The input point can also be dragged on the graph.
Used for integer powers. Negative powers require \(z\ne0\).
Used for \(n\)-th roots.

Example: \((-8)^{1/3}\) has three complex cube roots because the equation \(w^3=-8\) has three solutions.

Graph and output settings

For root modes, this highlights one branch/root.
Smaller values make the root animation slower.

Quick examples

Ready
Enter \(z\), choose an operation, then click “Calculate”.

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Frequently Asked Questions

How do you compute powers of complex numbers?

Write z in polar form z = r e^(i theta), then use De Moivre's theorem: z^m = r^m e^(i m theta).

How many nth roots does a complex number have?

A nonzero complex number has n distinct nth roots.

What is the formula for nth roots of a complex number?

If z = r e^(i theta), then the roots are w_k = r^(1/n) e^(i(theta + 2 pi k)/n), where k = 0, 1, ..., n-1.

What are the cube roots of -8?

The three cube roots of -8 are -2, 1 + sqrt(3)i, and 1 - sqrt(3)i.

Why are there multiple complex roots?

Complex angles repeat every 2 pi. When roots are taken, those repeated angles produce different directions.

What does z^(p/q) mean in the complex plane?

It means solving w^q = z^p, so it usually has q branch values.

Can zero have negative powers?

No. Negative powers of zero are undefined because they require division by zero.

Can I export all root values?

Yes. Use Download CSV to export every output value with rectangular form, modulus, and argument.