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Poisson Statistical Distribution (PMF, Mean/Variance, Examples)

What is the poisson statistical distribution, and how are probabilities such as \(P(X=k)\) and \(P(X\le k)\) computed for a given rate parameter \(\lambda\)?

Subject: Statistics Chapter: Discrete Random Variables and Their Probability Distributions Topic: The Poisson Probability Distribution Answer included
poisson statistical distribution poisson distribution poisson probability distribution discrete random variable rate parameter lambda probability mass function poisson process mean equals variance
Accepted answer Answer included

Poisson statistical distribution

The poisson statistical distribution (Poisson distribution) is a discrete probability distribution for a random count \(X\) of events occurring in a fixed time window, distance, area, or volume. The model is appropriate when events occur independently, the average rate is constant within the interval, and simultaneous events are negligible at the chosen measurement resolution.

The parameter \(\lambda\) represents the expected number of events in the interval. The probability of observing \(k\) events depends on \(\lambda\) and the factorial \(k!\).

Probability mass function

A Poisson-distributed random variable \(X\sim\text{Poisson}(\lambda)\) takes values \(k=0,1,2,\dots\) with probability mass function (PMF)

\[ P(X=k)=\frac{e^{-\lambda}\lambda^k}{k!}, \qquad k=0,1,2,\dots,\ \lambda>0 \]

The exponential factor \(e^{-\lambda}\) ensures that the total probability sums to 1 across all nonnegative integers.

Core properties and interpretation of \(\lambda\)

Property Statement Interpretation
Support \(k\in\{0,1,2,\dots\}\) Counts only
Mean \(E[X]=\lambda\) Average count per interval
Variance \(\operatorname{Var}(X)=\lambda\) Dispersion matches the mean under the model
Standard deviation \(\sigma=\sqrt{\lambda}\) Typical fluctuation scale
Additivity If \(X_1\sim\text{Poisson}(\lambda_1)\), \(X_2\sim\text{Poisson}(\lambda_2)\) independent, then \(X_1+X_2\sim\text{Poisson}(\lambda_1+\lambda_2)\) Combining independent intervals adds expected counts

Computing probabilities

Point probability

A single-count probability follows directly from the PMF. For example, if \(\lambda=2\) events per interval, the probability of exactly \(5\) events is

\[ P(X=5)=\frac{e^{-2}\cdot 2^5}{5!} =\frac{e^{-2}\cdot 32}{120} \approx 0.0360894 \]

Cumulative probability

Cumulative probabilities are sums of PMF values. For \(\lambda=2\),

\[ P(X\le 2)=P(X=0)+P(X=1)+P(X=2) =e^{-2}\left(1+\frac{2^1}{1!}+\frac{2^2}{2!}\right) \approx 0.6766764 \]

Right-tail probabilities use complements, such as \(P(X\ge 5)=1-P(X\le 4)\). With \(\lambda=2\), \[ P(X\ge 5)\approx 0.0526530 \]

\(\lambda\) Quantity Expression Approximate value
2 \(P(X=0)\) \(e^{-2}\) 0.1353353
2 \(P(X=5)\) \(e^{-2}\cdot 2^5/5!\) 0.0360894
2 \(P(X\le 2)\) \(\sum_{k=0}^{2} e^{-2}2^k/k!\) 0.6766764
2 \(P(X\ge 5)\) \(1-\sum_{k=0}^{4} e^{-2}2^k/k!\) 0.0526530

Visualization of the Poisson PMF for different \(\lambda\)

Poisson PMF bars for k = 0…12 (y-axis from 0.0 to 0.4) λ = 1 λ = 3 λ = 6 mean at k = λ λ = 1 Most mass near k = 0 and 1; mean = variance = 1 0.4 0.3 0.2 0.1 0.0 0 3 6 9 12 k P(X = k) λ λ = 3 Peak near k = 2 and 3; mean = variance = 3 0.4 0.3 0.2 0.1 0.0 0 3 6 9 12 k P(X = k) λ λ = 6 More symmetric around k ≈ 6; mean = variance = 6 0.4 0.3 0.2 0.1 0.0 0 3 6 9 12 k P(X = k) λ
Each panel plots \(P(X=k)\) for a Poisson random variable at a fixed \(\lambda\). The dashed line marks the mean location \(k=\lambda\). Increasing \(\lambda\) shifts the distribution rightward and spreads it out, with variability governed by \(\sigma=\sqrt{\lambda}\).

Rate and interval length

A common parameterization separates a rate \(r\) (events per unit time) and an exposure length \(t\). The expected count in the interval is \(\lambda=rt\). For example, a rate of \(r=2\) calls per minute over \(t=3\) minutes gives \(\lambda=6\), so the total call count in 3 minutes is modeled by \(\text{Poisson}(6)\) under constant-rate, independent-occurrence conditions.

Estimating \(\lambda\) from data

For independent observations \(x_1,\dots,x_n\) from \(\text{Poisson}(\lambda)\), the natural estimator of \(\lambda\) is the sample mean:

\[ \widehat{\lambda}=\frac{1}{n}\sum_{i=1}^{n} x_i \]

With unequal exposures \(t_i\) and counts \(x_i\), a rate estimate uses total counts divided by total exposure, \[ \widehat{r}=\frac{\sum_{i=1}^{n} x_i}{\sum_{i=1}^{n} t_i}, \qquad \widehat{\lambda}(t)=\widehat{r}\,t \]

Connections and approximations

The Poisson distribution arises as a limiting form of the binomial distribution when \(n\) is large, \(p\) is small, and \(\lambda=np\) is of moderate size. In that regime, \[ \text{Binomial}(n,p)\approx \text{Poisson}(\lambda=np) \]

For large \(\lambda\), the Poisson distribution becomes approximately normal: \[ X \approx N(\lambda,\lambda) \] with continuity adjustments improving tail approximations for integer counts.

Common pitfalls

Issue What changes Typical symptom in data
Non-constant rate within the interval \(\lambda\) varies with time or space Systematic patterns by time-of-day or location
Dependence or clustering of events Independence fails Variance larger than the mean (overdispersion)
Many simultaneous events at the same instant/resolution Discrete-time artifacts appear Excess mass at higher counts compared with Poisson
Excess zeros (structural zeros) Mixture mechanisms beyond Poisson Observed zeros far exceed Poisson predictions
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