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Strong Electrolytes: Dissociation, Ion Concentrations, and Conductivity

What are strong electrolytes in aqueous solution, and for a 0.100 M CaCl2(aq) solution what are [Ca2+], [Cl−], and the total dissolved-ion concentration assuming complete dissociation?

Subject: General Chemistry Chapter: Reactions in Aqueous Solutions Topic: Disociation and Ionization of Electrolytes Answer included
strong electrolytes electrolytes in water dissociation ionization conductivity complete dissociation strong acids strong bases
Accepted answer Answer included

Meaning of strong electrolytes

Strong electrolytes are substances that produce ions in water to an extent that is effectively complete at typical laboratory concentrations. Because the solution contains many mobile ions, it conducts electricity strongly.

In practice, “strong electrolyte” means the dissolved solute exists primarily as separated ions, so ion concentrations can be obtained directly from the formula and the solution molarity.

Dissociation vs ionization

Two related processes lead to ions in aqueous solution:

Process Typical solute type What happens in water Example equation
Dissociation Ionic compounds (salts) Pre-existing ions separate and become hydrated \(\mathrm{NaCl(s) \rightarrow Na^{+}(aq) + Cl^{-}(aq)}\)
Ionization Molecular acids/bases Molecules react with water to form ions \(\mathrm{HCl(g) \rightarrow H^{+}(aq) + Cl^{-}(aq)}\)

Which substances are strong electrolytes

Strong electrolytes in general chemistry fall into three common categories.

Category Criterion Common examples Notes
Soluble ionic compounds Salt that dissolves significantly in water \(\mathrm{NaCl}\), \(\mathrm{KNO_3}\), \(\mathrm{CaCl_2}\) Strong once dissolved; insoluble salts do not create many ions in solution.
Strong acids Essentially complete proton donation in water \(\mathrm{HCl}\), \(\mathrm{HBr}\), \(\mathrm{HI}\), \(\mathrm{HNO_3}\), \(\mathrm{HClO_4}\) \(\mathrm{H_2SO_4}\) is strong for the first ionization step.
Strong bases Essentially complete hydroxide release in water \(\mathrm{NaOH}\), \(\mathrm{KOH}\), \(\mathrm{Ba(OH)_2}\), \(\mathrm{Ca(OH)_2}\) Solubility can limit how much base dissolves, but the dissolved portion dissociates fully.

Worked example: ion concentrations for a strong electrolyte

Consider a \(0.100\ \mathrm{M}\) aqueous solution of calcium chloride, \(\mathrm{CaCl_2(aq)}\). As a strong electrolyte, it is treated as completely dissociated:

\[ \mathrm{CaCl_2(aq) \rightarrow Ca^{2+}(aq) + 2\,Cl^{-}(aq)} \]
  1. Relate ions to one formula unit. One \(\mathrm{CaCl_2}\) produces 1 \(\mathrm{Ca^{2+}}\) and 2 \(\mathrm{Cl^{-}}\).
  2. Multiply the solution molarity by stoichiometric coefficients. \[ [\mathrm{Ca^{2+}}] = 1 \times 0.100 = 0.100\ \mathrm{M} \] \[ [\mathrm{Cl^{-}}] = 2 \times 0.100 = 0.200\ \mathrm{M} \]
  3. Total dissolved-ion concentration (sum of ion molarities). \[ [\text{ions}]_{\text{total}} = [\mathrm{Ca^{2+}}] + [\mathrm{Cl^{-}}] = 0.100 + 0.200 = 0.300\ \mathrm{M} \]

Related concept: van’t Hoff factor for strong electrolytes

For colligative properties, the ideal van’t Hoff factor \(i\) is the number of ions produced per formula unit for a strong electrolyte (assuming complete dissociation and ideal behavior). For calcium chloride:

\[ \mathrm{CaCl_2 \rightarrow Ca^{2+} + 2\,Cl^{-}} \quad \Rightarrow \quad i \approx 3 \]

Real solutions may deviate slightly from the ideal due to ion pairing, especially at higher concentrations.

Visualization: complete dissociation of a strong electrolyte

Before: formula units in solution After: ions in solution (strong electrolyte) Ca2+ Cl Cl Ca2+ Cl Cl Ca2+ Cl Cl \(\mathrm{CaCl_2(aq)}\) present as units before dissociation is represented dissociation Ca2+ Cl Cl Cl Ca2+ Complete dissociation: \(\mathrm{CaCl_2(aq) \rightarrow Ca^{2+}(aq) + 2\,Cl^{-}(aq)}\) Many mobile ions → strong electrical conductivity
A strong electrolyte is represented by ions dispersed throughout the solution after dissociation; ion mobility explains high conductivity and enables direct stoichiometric ion-concentration calculations.

Final result for the example

For a \(0.100\ \mathrm{M}\) \(\mathrm{CaCl_2}\) solution treated as a strong electrolyte: \( [\mathrm{Ca^{2+}}] = 0.100\ \mathrm{M} \), \( [\mathrm{Cl^{-}}] = 0.200\ \mathrm{M} \), and the total dissolved-ion concentration is \(0.300\ \mathrm{M}\).

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