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Oxygen Difluoride Lewis Structure

What is the oxygen difluoride Lewis structure, including lone pairs, formal charges, and the resulting molecular shape?

Subject: General Chemistry Chapter: Chemical Bonds Topic: Lewis Structure of Group 6a Central Atoms Answer included
oxygen difluoride lewis structure OF2 lewis structure lewis dot structure valence electrons octet rule formal charge VSEPR AX2E2 bent molecular geometry
Accepted answer Answer included

Oxygen difluoride Lewis structure

The oxygen difluoride Lewis structure corresponds to the molecular formula OF2 with oxygen as the central atom bonded to two fluorine atoms. Single bonds satisfy the typical bonding preferences of fluorine, and oxygen completes an octet by retaining two lone pairs.

Compact description

Connectivity: F–O–F. Lone pairs: oxygen has 2 lone pairs; each fluorine has 3 lone pairs. Formal charges: all atoms have formal charge 0.

Valence-electron accounting

Valence electrons come from the periodic table group numbers: oxygen contributes 6 and each fluorine contributes 7. The total is

\[ 6 \;+\; 2 \times 7 \;=\; 20 \text{ valence electrons.} \]

Component Electron count Interpretation
Total valence electrons \(20\) Electrons available for bonds and lone pairs
Two single bonds (O–F and O–F) \(2 \times 2 = 4\) Two bonding pairs
Lone pairs on two fluorine atoms \(2 \times 6 = 12\) Three lone pairs per fluorine
Remaining for oxygen lone pairs \(20 - 4 - 12 = 4\) Two lone pairs on oxygen

Octets and electron-pair geometry

Each fluorine reaches an octet through one single bond plus three lone pairs. Oxygen reaches an octet through two single bonds plus two lone pairs. The electron-domain arrangement around oxygen is tetrahedral (four electron domains), while the molecular shape is bent because two domains are lone pairs.

Formal charge check

Formal charge is evaluated by

\[ \text{FC} \;=\; V \;-\; \left(N \;+\; \frac{B}{2}\right) \]

For oxygen in OF2, \(V=6\), \(N=4\) (two lone pairs), and \(B=4\) (two single bonds). This gives \(\text{FC}=6-(4+2)=0\). For each fluorine, \(V=7\), \(N=6\), and \(B=2\), giving \(\text{FC}=7-(6+1)=0\). Zero formal charges align with the dominant Lewis representation.

Visualization

The bent F–O–F arrangement reflects four electron domains around oxygen (two bonding pairs and two lone pairs). Lone pairs are shown as colored dots, while bonds and atom labels inherit the page text color.

Molecular polarity and oxidation state note

Fluorine is more electronegative than oxygen, so each O–F bond dipole points toward fluorine. The bent geometry prevents complete cancellation, so oxygen difluoride is polar. The oxidation-state assignment places oxygen at \(+2\) and each fluorine at \(-1\), an unusual case that remains consistent with fluorine’s strong tendency to form \(-1\) in compounds.

Common pitfalls

  • The central atom assignment places oxygen in the middle because fluorine typically forms only one bond in Lewis structures.
  • Double bonds are not favored for OF2; single bonds with full octets and zero formal charges dominate.
  • The electron-domain arrangement is tetrahedral around oxygen, while the molecular shape is bent due to two lone pairs.
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