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Matter Cannot Be Created or Destroyed: Conservation of Mass

A sealed flask contains 15.0 g of CaCO\(_3\) that decomposes by heating according to CaCO\(_3\)(s) → CaO(s) + CO\(_2\)(g); if 8.40 g of CaO is produced, what mass of CO\(_2\) forms and how does this illustrate that matter cannot be created or destroyed?

Subject: General Chemistry Chapter: Chemical Compounds Topic: Law of Conservation of Mass Answer included
matter cannot be created or destroyed law of conservation of mass conservation of mass closed system mass balance Antoine Lavoisier chemical reaction balanced equation
Accepted answer Answer included

Problem

The statement “matter cannot be created or destroyed” is tested using a closed (sealed) decomposition reaction. A sealed flask contains 15.0 g of calcium carbonate, CaCO3. When heated it decomposes:

\[ \text{CaCO}_3(s)\rightarrow \text{CaO}(s)+\text{CO}_2(g) \]

After completion, 8.40 g of CaO is measured. Determine the mass of CO2 produced.

Concept: conservation of mass

In a closed system, total mass remains constant during a chemical reaction. Atoms are rearranged into new substances, but the total amount of matter is unchanged. This is the operational meaning of “matter cannot be created or destroyed.”

\[ m_{\text{reactants}} = m_{\text{products}} \]

Step-by-step solution

Step 1: Identify what mass is conserved

The flask is sealed, so no gas escapes and no material enters. Therefore, the initial mass of CaCO3 must equal the combined masses of CaO and CO2 after reaction.

Step 2: Write the mass-balance equation

\[ m(\text{CaCO}_3)=m(\text{CaO})+m(\text{CO}_2) \]

Step 3: Substitute values and solve for \(m(\text{CO}_2)\)

\[ 15.0\ \text{g} = 8.40\ \text{g} + m(\text{CO}_2) \]
\[ m(\text{CO}_2)=15.0\ \text{g}-8.40\ \text{g}=6.60\ \text{g} \]

Result

The mass of carbon dioxide produced is \(6.60\ \text{g}\). The total product mass is \(8.40\ \text{g}+6.60\ \text{g}=15.0\ \text{g}\), matching the initial reactant mass, which directly illustrates that matter cannot be created or destroyed in a closed system.

Mass summary table

Stage Substance(s) Mass (g) Total mass (g)
Before heating CaCO3 15.0 15.0
After heating (sealed flask) CaO + CO2 8.40 + 6.60 15.0

Visualization: mass balance in a sealed reaction

The diagram shows the same total mass on both sides (reactants vs products) for a closed system. The right pan separates the solid CaO and the gaseous CO2, but the sum remains unchanged.

CaCO3 15.0 g CaO 8.40 g CO2 = 6.60 g Closed system: total mass stays the same Reactants Products
The left pan represents the initial 15.0 g of CaCO3. After decomposition, the right pan contains 8.40 g CaO and 6.60 g CO2, whose sum remains 15.0 g, consistent with the law of conservation of mass.

Final answer

\(m(\text{CO}_2)=6.60\ \text{g}\), and the equality of total mass before and after the reaction in a sealed flask demonstrates that matter cannot be created or destroyed.

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