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Is mercury solid in its standard state?

Is mercury solid in its standard state, and how do its melting point and boiling point show its physical state at standard conditions?

Subject: General Chemistry Chapter: Liquids and Solids Topic: Vapour Pressure Answer included
is mercury solid in its standard state mercury standard state Hg standard state mercury liquid at room temperature standard state definition melting point of mercury boiling point of mercury phase of mercury
Accepted answer Answer included

Mercury is not solid in its standard state. Elemental mercury, Hg, is a liquid at standard thermodynamic conditions, so the standard-state physical form is commonly written as Hg(l).

Standard state meaning for an element

The standard state of an element is its most stable physical form at a specified pressure (commonly 1 bar) and a specified temperature used for standard thermodynamic tables (commonly 298.15 K). For mercury, that stable form at these conditions is the liquid phase.

Phase justification from melting and boiling points

The phase at a given pressure is determined by comparing the temperature to the melting point and boiling point at that pressure. Mercury has an unusually low melting point for a metal, so room-temperature conditions lie in the liquid region.

Quantity Symbol Value Phase implication at 1 bar (typical)
Melting point \(T_m\) \(-38.83\,^\circ\text{C}\) (approx.) Below \(T_m\): solid Hg(s)
Standard thermodynamic temperature \(T^\circ\) \(298.15\,\text{K} = 25.00\,^\circ\text{C}\) Between \(T_m\) and \(T_b\): liquid Hg(l)
Boiling point \(T_b\) \(356.73\,^\circ\text{C}\) (approx.) Above \(T_b\): gaseous Hg(g)

A Kelvin comparison emphasizes the ordering. Mercury’s melting point converts to Kelvin using \(T(\text{K}) = T(^\circ\text{C}) + 273.15\).

\[ T_m = -38.83 + 273.15 = 234.32\ \text{K} \]

\[ T^\circ = 298.15\ \text{K} \quad \text{and} \quad 234.32\ \text{K} < 298.15\ \text{K} \ll (356.73 + 273.15)\ \text{K} \]

The inequality places \(T^\circ\) above the melting point and well below the boiling point at comparable pressure, so Hg is liquid in its standard state.

STP and standard state language

Standard state in thermodynamics is not identical to STP. A common STP convention uses \(0\,^\circ\text{C}\) with a specified pressure, while thermodynamic standard-state tables commonly use \(25\,^\circ\text{C}\) and 1 bar. Mercury remains liquid at \(0\,^\circ\text{C}\) as well because \(0\,^\circ\text{C} > -38.83\,^\circ\text{C}\).

Temperature band showing mercury phase at 1 bar A horizontal temperature axis marks the melting point, standard temperature, and boiling point. The liquid region between melting and boiling is highlighted, indicating mercury is liquid at standard state. Temperature (°C), typical 1 bar interpretation Solid region Liquid region Gas region −60 400 Hg(s) ⇄ Hg(l) at \(T_m \approx -38.83\,^\circ\text{C}\) Standard \(25\,^\circ\text{C}\) lies in the liquid region Hg(l) ⇄ Hg(g) at \(T_b \approx 356.73\,^\circ\text{C}\)
The highlighted band marks the liquid temperature interval between mercury’s melting point and boiling point. The standard thermodynamic temperature \(25\,^\circ\text{C}\) falls inside this interval, so Hg is liquid in its standard state.

Common pitfalls

  • Standard state vs STP confusion (standard thermodynamic tables often use \(298.15\,\text{K}\), while STP commonly uses \(273.15\,\text{K}\)).
  • Pressure convention mismatch (1 bar vs 1 atm) treated as identical without noting the definition being used.
  • Melting point comparison omitted, leading to an incorrect assumption that all metals are solid at standard conditions.
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