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Ionization Energy and the Periodic Table: Trend and Period 3 Ordering

Using periodic table trends, how does first ionization energy change across periods and down groups, and what is the correct lowest-to-highest order for the first ionization energies of Na, Mg, Al, Si, P, S, Cl, and Ar?

Subject: General Chemistry Chapter: Atoms Topic: Atomic Structure Answer included
ionization energy periodic table first ionization energy periodic trend effective nuclear charge shielding atomic radius valence electron subshell
Accepted answer Answer included

Definition of first ionization energy

The first ionization energy (often written as \(IE_1\)) is the energy required to remove the most weakly held electron from a gaseous neutral atom:

\[ X(g) \rightarrow X^{+}(g) + e^{-} \]

A larger \(IE_1\) means the valence electron is held more strongly by the nucleus.

Periodic table trend: across a period and down a group

Ionization energy on the periodic table is governed mainly by the competition between nuclear attraction and shielding by inner electrons (often summarized by effective nuclear charge \(Z_{\mathrm{eff}}\)).

Direction on periodic table Typical change in \(IE_1\) Primary reasons
Left → right across a period Increases \(Z\) increases while shielding changes modestly within the same principal shell, so \(Z_{\mathrm{eff}}\) rises; atomic radius contracts and valence electrons are held more tightly.
Top → bottom down a group Decreases Valence electrons occupy higher principal energy levels (larger \(n\)), farther from the nucleus; increased shielding reduces attraction, making removal easier.

Important exceptions (why “generally” is necessary)

Two recurring exceptions appear in many periods: (1) starting a new p subshell, and (2) pairing electrons within a p subshell.

Exception pattern Typical comparison Chemical explanation
New subshell begins (s → p) Group 2 vs Group 13 (e.g., Mg vs Al) A p electron is, on average, higher in energy and less penetrating than an s electron in the same shell, so it is easier to remove; \(IE_1\) can dip at the first p element.
Electron pairing in p orbitals Group 15 vs Group 16 (e.g., P vs S) When one p orbital becomes paired, electron–electron repulsion increases; removing one paired electron can require slightly less energy, creating a small dip.

Apply the trend: ordering first ionization energies in Period 3

Consider Period 3 elements: Na, Mg, Al, Si, P, S, Cl, Ar. The overall expectation is an increase from Na → Ar, with two dips at Al (start of p subshell) and S (paired p electron).

Correct lowest-to-highest order: \[ IE_1(\mathrm{Na}) < IE_1(\mathrm{Al}) < IE_1(\mathrm{Mg}) < IE_1(\mathrm{Si}) < IE_1(\mathrm{S}) < IE_1(\mathrm{P}) < IE_1(\mathrm{Cl}) < IE_1(\mathrm{Ar}) \]

Justification using electron configurations (valence level \(n=3\))

The valence-shell patterns explain both the general rise (increasing \(Z_{\mathrm{eff}}\)) and the two anomalies.

Element Valence configuration Ionization-energy reasoning
Na 3s1 Single 3s electron is relatively easy to remove → very low \(IE_1\).
Mg 3s2 Higher \(Z_{\mathrm{eff}}\) than Na and a filled 3s subshell → higher \(IE_1\).
Al 3s2 3p1 First p electron is less penetrating and easier to remove than Mg’s 3s electron → dip: \(IE_1(\mathrm{Al}) < IE_1(\mathrm{Mg})\).
Si 3s2 3p2 Increasing \(Z_{\mathrm{eff}}\) across the period strengthens attraction → \(IE_1\) rises from Al.
P 3s2 3p3 Half-filled p subshell is relatively stable → higher \(IE_1\) than Si.
S 3s2 3p4 One p orbital is paired, increasing repulsion → slight dip: \(IE_1(\mathrm{S}) < IE_1(\mathrm{P})\).
Cl 3s2 3p5 Strong \(Z_{\mathrm{eff}}\) and small radius → \(IE_1\) rises again.
Ar 3s2 3p6 Closed-shell noble gas configuration → highest \(IE_1\) in the period.

Visualization: qualitative first ionization energy trend across Period 3

Element (Period 3) Relative \(IE_1\) Na Mg Al Si P S Cl Ar Dip: start of 3p (Al) Dip: paired p electron (S) General increase →
The line shows the typical increase in first ionization energy across Period 3, with two well-known exceptions: a dip at Al (first 3p electron) and a dip at S (electron pairing in a 3p orbital).

Final takeaway for ionization energy on the periodic table

Ionization energy periodic table trends follow increasing \(Z_{\mathrm{eff}}\) across periods and increasing distance and shielding down groups. Across Period 3, these principles yield the order \( \mathrm{Na} < \mathrm{Al} < \mathrm{Mg} < \mathrm{Si} < \mathrm{S} < \mathrm{P} < \mathrm{Cl} < \mathrm{Ar} \), with Al and S as the key exceptions.

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