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Average mass of two beryllium atoms

What is the average mass of two beryllium atoms, and what is the total mass of the two-atom sample?

Subject: General Chemistry Chapter: Atoms Topic: Atomic Mass Answer included
average mass of two beryllium atoms beryllium atomic mass atomic mass unit amu u to grams standard atomic weight isotopic average mass mass of two atoms
Accepted answer Answer included

Meaning of “average mass” for two atoms

The phrase average mass of two beryllium atoms can refer to the mean mass per atom in a two-atom sample: \(\bar{m} = \dfrac{m_1 + m_2}{2}\). When both atoms are beryllium taken from the same natural sample, the expected mean per atom equals the standard (periodic-table) atomic mass of beryllium.

Numerical values use the common periodic-table average atomic mass of beryllium: \(m_{\mathrm{Be}} \approx 9.0122\,\mathrm{u}\). The atomic mass unit conversion uses \(1\,\mathrm{u} = 1.66053906660\times 10^{-24}\,\mathrm{g}\).

Average mass per atom and total mass for two atoms

\[ \bar{m} = \frac{m_1+m_2}{2}. \]

For two atoms of the same element modeled by the standard atomic mass \(m_{\mathrm{Be}}\), \[ \bar{m} = \frac{m_{\mathrm{Be}}+m_{\mathrm{Be}}}{2} = m_{\mathrm{Be}} \approx 9.0122\,\mathrm{u}. \]

The total mass of the two-atom sample is \[ m_{\text{total}} = m_1+m_2 = 2\,m_{\mathrm{Be}} \approx 2\times 9.0122\,\mathrm{u} = 18.0244\,\mathrm{u}. \]

Conversion to grams

The mass of one atom in grams follows from the atomic mass unit: \[ m_{\mathrm{Be}}(\mathrm{g}) = \left(9.0122\,\mathrm{u}\right)\left(1.66053906660\times 10^{-24}\,\mathrm{g/u}\right) \approx 1.4965\times 10^{-23}\,\mathrm{g}. \]

The mass of two beryllium atoms in grams is \[ m_{\text{total}}(\mathrm{g}) = 2\,m_{\mathrm{Be}}(\mathrm{g}) \approx 2.9930\times 10^{-23}\,\mathrm{g}. \]

Interpretation in a natural-isotope context

The standard atomic mass is a weighted average over naturally occurring isotopes. A two-atom sample can, in principle, contain different isotopes, so \(m_1\) and \(m_2\) can differ. Even in that case, the expected value of the sample mean remains the weighted-average atomic mass: \[ \mathbb{E}[\bar{m}] = \mathbb{E}\!\left[\frac{m_1+m_2}{2}\right] = \frac{\mathbb{E}[m_1]+\mathbb{E}[m_2]}{2} = \mathbb{E}[m] = m_{\mathrm{Be}}. \]

Numerical summary

Quantity Expression Value
Average mass per atom (two-atom sample) \(\bar{m} = (m_1+m_2)/2\) \(\bar{m} \approx 9.0122\,\mathrm{u}\)
Total mass of two atoms \(m_{\text{total}} = 2\,m_{\mathrm{Be}}\) \(m_{\text{total}} \approx 18.0244\,\mathrm{u}\)
Mass of one atom in grams \(m_{\mathrm{Be}}(\mathrm{g}) = m_{\mathrm{Be}}(\mathrm{u})\times (1\,\mathrm{u})\) \(\approx 1.4965\times 10^{-23}\,\mathrm{g}\)
Mass of two atoms in grams \(m_{\text{total}}(\mathrm{g}) = 2\,m_{\mathrm{Be}}(\mathrm{g})\) \(\approx 2.9930\times 10^{-23}\,\mathrm{g}\)

Visualization of mean versus total for two atoms

Two beryllium atoms: average mass per atom and total mass Two colored circles represent two beryllium atoms, each labeled with an approximate mass of 9.0122 u. Arrows point to two result boxes: the average mass per atom (9.0122 u) and the total mass of the pair (18.0244 u). A dark-mode palette is provided inside the SVG. Two beryllium atoms: mean per atom vs total mass Be 9.0122 u Be 9.0122 u Average mass per atom m̄ = 9.0122 u Total mass of two atoms m_total = 18.0244 u Mean per atom equals the element’s atomic mass; total mass scales with the number of atoms.
The mean mass per atom in a two-atom beryllium sample matches the atomic mass of beryllium, while the total mass of the pair is twice that value.
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