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Ferns and Photosynthesis: Light Response Curve Calculations

A shade-adapted fern has net photosynthesis modeled by \(P_n(I)=P_{\max}\left(1-e^{-\alpha I/P_{\max}}\right)-R_d\). If \(P_{\max}=8\), \(\alpha=0.05\), and \(R_d=1.2\), what is \(P_n\) at \(I=200\), and what is the light compensation point where \(P_n=0\)?

Subject: Biology Chapter: Photosynthesis and Plant Energy Topic: Factors Affecting Photosynthesis Answer included
ferns fern photosynthesis light response curve net photosynthesis light compensation point dark respiration photosynthetic efficiency PPFD
Accepted answer Answer included

Ferns are seedless vascular plants whose fronds carry out photosynthesis, often under forest-canopy shade where light is a limiting factor. A common way to quantify how light controls fern carbon gain is a light-response curve for net photosynthesis \(P_n\), which balances light-driven CO2 uptake against respiratory CO2 loss.

Model and parameter meaning

Net photosynthesis model (saturating exponential):

\[ P_n(I)=P_{\max}\left(1-e^{-\alpha I/P_{\max}}\right)-R_d \]

\(I\) = light intensity (commonly PPFD, \(\mu\text{mol photons}\cdot\text{m}^{-2}\cdot\text{s}^{-1}\));
\(P_{\max}\) = light-saturated gross photosynthesis capacity;
\(\alpha\) = initial slope (photosynthetic efficiency at low light);
\(R_d\) = dark respiration rate (CO2 released even in light).

Step 1: Compute \(P_n\) at \(I=200\)

  1. Substitute \(P_{\max}=8\), \(\alpha=0.05\), \(R_d=1.2\), \(I=200\): \[ P_n(200)=8\left(1-e^{-(0.05\cdot 200)/8}\right)-1.2 \]
  2. Compute the exponent: \[ \frac{0.05\cdot 200}{8}=\frac{10}{8}=1.25 \quad\Rightarrow\quad e^{-1.25}\approx 0.2865 \]
  3. Evaluate the bracket and multiply by \(8\): \[ 1-0.2865=0.7135 \quad\Rightarrow\quad 8\cdot 0.7135\approx 5.708 \]
  4. Subtract respiration: \[ P_n(200)\approx 5.708-1.2=4.508\approx 4.51 \]

Result: \(P_n(200)\approx 4.51\) (in the same rate units as \(P_{\max}\) and \(R_d\), commonly \(\mu\text{mol CO}_2\cdot\text{m}^{-2}\cdot\text{s}^{-1}\)).

Step 2: Find the light compensation point \(I_c\) where \(P_n=0\)

The compensation point is the light level where CO2 gained by photosynthesis exactly balances CO2 lost to respiration, so net exchange is zero.

  1. Set \(P_n(I_c)=0\): \[ 0=P_{\max}\left(1-e^{-\alpha I_c/P_{\max}}\right)-R_d \]
  2. Rearrange: \[ P_{\max}\left(1-e^{-\alpha I_c/P_{\max}}\right)=R_d \quad\Rightarrow\quad 1-e^{-\alpha I_c/P_{\max}}=\frac{R_d}{P_{\max}} \]
  3. Isolate the exponential term: \[ e^{-\alpha I_c/P_{\max}}=1-\frac{R_d}{P_{\max}} \]
  4. Take natural logs and solve for \(I_c\): \[ -\frac{\alpha I_c}{P_{\max}}=\ln\!\left(1-\frac{R_d}{P_{\max}}\right) \quad\Rightarrow\quad I_c=-\frac{P_{\max}}{\alpha}\ln\!\left(1-\frac{R_d}{P_{\max}}\right) \]
  5. Substitute values: \[ I_c=-\frac{8}{0.05}\ln\!\left(1-\frac{1.2}{8}\right) =-160\cdot \ln(0.85) \] Since \(\ln(0.85)\approx -0.1625\), \[ I_c\approx -160\cdot(-0.1625)=26.0 \]

Result: The light compensation point is \(I_c\approx 26.0\) (same light units as \(I\)).

Visualization: fern light-response curve \(P_n(I)\)

\(I_c\approx 26\) \(I=200\) Light intensity \(I\) Net photosynthesis \(P_n\) 0 200 400 600 \(P_n(200)\approx 4.51\) dashed line: \(P_n=0\)
The curve shows how a fern’s net photosynthesis \(P_n\) increases rapidly at low light, then approaches a saturation region; the light compensation point \(I_c\) is where the curve crosses \(P_n=0\).

Biological interpretation for ferns

Quantity Computed value Meaning in fern physiology
Dark respiration \(R_d\) \(1.2\) Baseline CO2 loss in the dark; raises the light level needed to break even.
Light compensation point \(I_c\) \(\approx 26.0\) Below this light, a fern frond is a net CO2 source; above it, net carbon gain begins.
Net photosynthesis at \(I=200\) \(\approx 4.51\) Moderate-light understory conditions can still yield strong net CO2 uptake for shade-adapted ferns.

Optional extension: “near-saturation” light level

A practical benchmark is the light intensity where gross photosynthesis reaches \(95\%\) of \(P_{\max}\), meaning \(P_{\max}(1-e^{-\alpha I/P_{\max}})=0.95\cdot P_{\max}\).

\[ 1-e^{-\alpha I/P_{\max}}=0.95 \quad\Rightarrow\quad e^{-\alpha I/P_{\max}}=0.05 \quad\Rightarrow\quad I=-\frac{P_{\max}}{\alpha}\ln(0.05) \]

\[ I\approx -\frac{8}{0.05}\ln(0.05)= -160\cdot \ln(0.05)\approx 479 \]

This indicates the modeled fern would approach saturation only under substantially brighter light than the compensation point, consistent with a strongly saturating response.

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